1 / 4

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ).

The Great Gummy Worm Sacrifice. Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. 1. Write a balanced chemical equation for the reaction:.

connor
Download Presentation

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ).

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. The Great Gummy Worm Sacrifice Today, we will burn a gummy worm containing 2.1 g of sucrose (C12H22O11). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. 1. Write a balanced chemical equation for the reaction: 2. The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose

  2. The Great Gummy Worm Sacrifice Today, we will burn a gummy worm containing 2.1 g of sucrose (C12H22O11). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. 1. Write a balanced chemical equation for the reaction: +5 640kJ C12H22O6 + O2 --> CO2 + H2O 11 12 12 2. The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation.

  3. The Great Gummy Worm Sacrifice = Today, we will burn a gummy worm containing 2.1 g of sucrose (C12H22O11). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. Write a balanced chemical equation for the reaction: +5 640kJ C12H22O6 + O2 --> CO2 + H2O 11 12 12 The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 2.1g C12H22O11 gO2 molC12H22O11 12 mol O2 32.00 1 1 molC12H22O11 1 mol O2 342.30 gC12H22O11 2.36gO2

  4. The Great Gummy Worm Sacrifice Today, we will burn a gummy worm containing 2.1 g of sucrose (C12H22O11). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases 5 640 000 joules of energy. Write a balanced chemical equation for the reaction: +5 640kJ C12H22O6 + O2 --> CO2 + H2O 11 12 12 The reaction releases 5 640 000 joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose 35kJ or 35 000J 2.1g C12H22O11 molC12H22O11 5640 kJ 1 = 1 molC12H22O11 342.30 gC12H22O11 That’s a lot of energy from just 2.1 grams of sucrose! It sounds dangerous. Let’s try it!

More Related