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3/11/2013 Standards : 6 (Solutions) O bjectives : ● Students will be able to calculate problems involving Molarity (M) and molality (m) D O NOW : 1. Calculate M (molarity) of a solution with 4.7 L of solution in which there are 2.2 mol of NaClO4 H OMEWORK :
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3/11/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate problems involving Molarity (M) and molality (m) DO NOW: 1. Calculate M (molarity) of a solution with 4.7 L of solution in which there are 2.2 mol of NaClO4 HOMEWORK: 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c) 5 pts (Std 6) 2. Two PRINTS (see website) 3. HANDOUTS TODAY - Tutorial Ch 15.1 - What Are Solutions, Ch 15.2 - Molarity - Molality - Colligative Properties Std 6 =========================================================== STAMPS: ● Journal 3/8 1. App A, p. 880 1-2 (1 pt) Std 6 2. Ch 15.2 p. 464-465 PP's 11-16 (4 pts) Std 6
Units of measure in Henry's Law S (solubility) g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL) P (pressure) atm, mmHg, Torr, kPa, Pa, psi (any unit of pressure is OK)
SOLVATION ANIMATION http://group.chem.iastate.edu/Greenbowe/sections/projectfolder/ flashfiles/thermochem/solutionSalt.html Demo - see video made in class yesterday 1. agitation 2. increase surface area 3. temperature
Units of measure in Henry's Law S (solubility) g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL) P (pressure) atm, mmHg, Torr, kPa, Pa, psi (any unit of pressure is OK)
M Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity Molarity
molarity M = mol L solute solution molarity
1 Calculate the molarity of a solution having 15.0 g NaCl in 2.80 L of water (volume of solution is still 2.80 L). Molar mass Cl = 35.5 Molar mass Na = 23.0 In your answer, use 3 sig. figs and do not use any units of measure. NUMBER ONLY
How to derive equality with prefixes What is 1 mL equal to in terms of L ? 1 m = (milli-) = 1000 1 mL = L 1000 1 x 1000 mL = L 1000 x 1000 1 x 1000 1000 x mL = L 1000 1000 mL = 1 L
How to derive equality with prefixes What is 1 kg equal to in terms of g ? k = (kilo-) = 1000 1 kg = 1000 g
PREFIXES Summary Is it 1000 kg = 1 g or 1000 g = 1 kg ? Make -- prefix letter x its mass unit (or volume) = prefix value x its mass unit 1 kg = 1000 g 1 kL = 1000 L 1 1 mL = L 1000 1 1 mg = g 1000
1 1 kg = 1000 g 1 mL = L 1000 Everything in green will be a fraction. Everything in blue will be a fraction.
Big Bigger http://mrwiggersci.com/chem/Tutorials/conv-units-all-prefixes.htm
M Molarity
2 What is the value of S if 25.0 g of gas is dissolved in 1.00 L of water? Number only 3 sig figs only no units of measure
3 What is the solubility of a gas if 25.0 g of the gas will dissolve in 1.00 L of water. Number only 3 sig figs only no units of measure
` possible solutes: a. salt (NaCl) b. sugar (sucrose) c. MgCl2 d. C (smaller portion of steel) e. paint pigments possible solvents: f. water g. iron (Fe major portion of steel) h. laquer thinner p. 463
3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percent DO NOW: 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 HOMEWORK: None =========================================================== STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c) 5 pts (Std 6) AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and Mass% & Molarity Lab Sheet) (1 pts) Std 6
For Quiz 3.3 number correct x 2.4 = points earned 60 = total possible
PREFIXES Summary Is it 1000 kg = 1 g or 1000 g = 1 kg ? Make -- prefix letter x its mass unit (or volume) = prefix value x its mass unit 1 1 mL = L 1 kg = 1000 g 1000 1 1 kL = 1000 L 1 mg = g 1000
answers: 69. 3.9% 70. 33.6% 71. 25% 77. a. 0.02 M (mol/L) b. 0.27 M (mol/L) c. 0.0847 M (mol/L) 78. a. 0.02 M mol b. 0.00625 mol c. 0.648 mol
3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percent DO NOW: 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 HOMEWORK: None =========================================================== STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p. 466 17-20 and Ch 15 Assess. p. 485 76 (a, b, & c) 5 pts (Std 6) AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and Mass% & Molarity Lab Sheet) (1 pts) Std 6
3/14/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate boiling point INcreases, and freezing point DEcreases. ● Demonstrate conducive solutions. Students will be able to recognize compounds that ionize (make 2 or more particles, salts, acids & bases) as different from those who don't ionize (sugar). DO NOW: 1. Name 3 kinds of substances ionize in water, and give one example of each? HOMEWORK: 1. Ch 15 Assess p. 485 79 (a,b,c), Ch 15.4 p. 475 33, 34, Ch 15 Assess p. 485 87 (a,b,c) (5 pts ) Std 6 (total problems = 8) =========================================================== STAMPS: ● Journal 3/13 (for periods 1,3,5) or 3/14 (for periods 2,6) 1. Ch 15 Assess - p. 484 69-71 and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 Answers: 78 a = 0.0320 mol; b = 0.00625 mol ; c = 0.648 mol 79 a = 0.0859 g; b = 34.6 g; c = 5.91 g 87 a = fp = 10.2 deg C, bp = 103.8 deg C b = fp = -115.8 deg C, bp = 79.1 deg C c = fp = -1.0 deg C, bp = 83.3 deg C period 2 was in assembly, which I photographed. It was on driving safely.
mole solute M = molarity = L solution mole solute m = molality = kg solvent
Boiling & freezing points of water can be changed by dissolving: ionic compounds (salts, acids, bases) non-ionic compounds (like sugar that don't form ions) BP 100°C 0°C FP
BIGGER changes More particles in the changes shown in charts p. 474 p. 472
BP Kb°C/m 100°C Kf°C/m 0°C FP
BIGGER changes More particles in the changes shown in charts p. 474 p. 472
mol (solute) molaltiy = kg (kg solvent)
mol (solute) molaltiy = kg (kg solvent)
mol (solute) molaltiy = kg (kg solvent)
BIGGER changes More particles in the changes shown in charts p. 474 p. 472
3/15/2013 Standards:6 (Solutions) Objectives: ●Polish skills learned in this chapter DO NOW: 1. Due end of period (8 points): Directions: All problems require calculations. So, show given, find, and calculations. Each problem is worth one point. p. 484 67 1 x 101 atm p. 487 3 a 71 25% 4 c p. 485 78 (b) 0.00625 mol 5 b 89 fp = -6.46 deg C bp = 101.8 deg HOMEWORK: Enjoy your week off and Think about Easter =========================================================== STAMPED: ● Journal 3/14 1. Ch 15 Assess p. 485 79 (a,b,c), Ch 15.4 p. 475 33, 34, Ch 15 Assess p. 485 87 (a,b,c) (5 pts ) Std 6