60 likes | 220 Views
LINEAR MOMENTUM: MOMENTUM – A vector quantity defined as the product of an object’s mass and velocity B. FORMULA – momentum = mass x velocity p = m x v C. UNITS – kgm/s D. EXAMPLES:. PROBLEM:
E N D
LINEAR MOMENTUM: • MOMENTUM – A vector quantity defined as the product • of an object’s mass and velocity • B. FORMULA – momentum = mass x velocity • p = m x v • C. UNITS – kgm/s • D. EXAMPLES:
PROBLEM: 1.A 2250kg pickup truck has a velocity of 25m/s to the east. What is the momentum of the truck? 2. What velocity must a car with a mass of 1210kg have in order to have the same momentum as question #1? 3. An ostrich with a mass of 146kg is running to the right with a velocity of 17m/s. Find the momentum of the ostrich. 4. A 21kg child is riding a 5.9kg bike with a velocity of 4.5m/s to the northwest. a. Find the total momentum b. Find the momentum of the child c. Find the momentum of the bike
IMPULSE: • IMPULSE – For a constant external force, the product of • the force and the time over which it acts on an object. • A change in momentum. • B. FORMULA – Force x time interval = change in momentum • F = ma = m x v/t = Dp/Dt • FDt = Dp = mvf – mvi • C. UNITS – kgm/s and always a direction. • D. EXAMPLES:
PROBLEMS: • A 1400kg car moving westward with a velocity of 15 m/s collides • with a utility pole and is brought to rest in 0.30s. Find the • magnitude of the force exerted on the car during the collision. • 2. Find the force exerted in question one if the speed is doubled. • 3. A .40kg soccer ball approaches a player horizontally with a velocity of • 18m/s to the north. The player strikes the ball with a velocity of • 22m/s in the opposite direction. Find the impulse on the ball. • NOTE: Extending the time interval over which a constant force is • applied allows a smaller force to cause a greater change • in momentum than would result if the force were applied • for a very short time.
Stopping times and distances depend on the • Impulse-Momentum Theorem. • A 2250kg car traveling to the west is slowed down uniformly from • 20.0m/s to 5.00m/s in 4.00s. What constant force acted on the car • during this time? How far did the car travel during the deceleration? • 2. How long would it take the car to come to a complete stop? • 3. What would be the total stopping distance? • 4. What if the car was 3250kg, how much force would be required to • cause the same acceleration as #1? • 5. How far would the car travel before stopping?
CONCEPT CHALLENGE: EGG DROP!!!!!!!