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EXAMPLE 1

Find the measure of each arc of P , where RT is a diameter. c. a. RTS. RST. RS. b. a. RS is a minor arc, so mRS = m RPS = 110 o. b. –. RTS is a major arc, so mRTS = 360 o 110 o = 250 o. c. RT is a diameter, so RST is a semicircle, and mRST = 180 o. EXAMPLE 1.

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EXAMPLE 1

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  1. Find the measure of each arc of P, where RTis a diameter. c. a. RTS RST RS b. a. RSis a minor arc, so mRS=mRPS=110o. b. – RTSis a major arc, so mRTS = 360o 110o = 250o. c. RT is a diameter, so RSTis a semicircle, and mRST=180o. EXAMPLE 1 Find measures of arcs SOLUTION

  2. Survey a. = + A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. a. mAC mAB mBC mAC EXAMPLE 2 Find measures of arcs SOLUTION = 29o + 108o = 137o

  3. Survey b. A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. mACD = mAC + mCD b. mACD EXAMPLE 2 Find measures of arcs SOLUTION = 137o + 83o = 220o

  4. Survey – mADC = 360o A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. c. mAC c. mADC EXAMPLE 2 Find measures of arcs SOLUTION = 360o – 137o = 223o

  5. Survey A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. mEBD = 360o – mED d. d. mEBD EXAMPLE 2 Find measures of arcs SOLUTION = 360o – 61o = 299o

  6. for Examples 1 and 2 GUIDED PRACTICE Identify the given arc as a major arc, minor arc, or semicircle, and find the measure of the arc.

  7. 1 . TQ TQis a minor arc, so m TQ=120o. 2 . QRT QRTis a major arc, so m QRT=240o. for Examples 1 and 2 GUIDED PRACTICE SOLUTION SOLUTION

  8. 3 TQRis a semicircle, so m TQR =180o. 4 . TQR . QS QSis a minor arc, so m QS =160o. for Examples 1 and 2 GUIDED PRACTICE SOLUTION SOLUTION

  9. 5 TSis a minor arc, so m TS =80o. 6 . TS . RST RSTis a semicircle, so m RST =180o. for Examples 1 and 2 GUIDED PRACTICE SOLUTION SOLUTION

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