460 likes | 708 Views
Introduction Roman Numerals Counting and Arithmetic Converting from Base 10. 100’s place. 10’s place. 1’s place. . We use a base 10 system with 10 digits, they are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. This is the decimal place – value system. 437 = 4 × 10 2 + 3 × 10 1 + 7 × 10 0.
E N D
Introduction Roman Numerals Counting and Arithmetic Converting from Base 10
100’s place 10’s place 1’s place • We use a base 10 system with 10 digits, they are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. • This is the decimal place – value system. 437 = 4 × 102 + 3 × 101 + 7 × 100
Roman Numerals • There is no place-value • The letters have fixed values • They are ordered from largest to smallest • If a letter representing a smaller value comes before a larger one it is subtracted
Roman Numerals Rules • The letters should be arranged from largest to smallest. • 1510 is written MDX, largest to smallest • Only powers of ten can be repeated. • Don’t repeat a letter more than three times in a row. • 100 is written LL, not XXXXXXXXXX
Roman Numerals Rules • Numbers can be written using subtraction. A letter with a smaller value precedes one of the larger value. The smaller number is then subtracted from the larger number. • Only powers for ten (I, X, C, M) can be subtracted. • The smaller letter must be either the first letter or preceded by a letter at least ten times greater than it. • CCXLIII = 100 + 100 + (50 – 10) + 1 + 1 + 1= 243
Write in Roman Numerals XXI • 21 • 32 • 515 • 900 • 1005 • 1954 • 3592 XXXII DXV CM MV MCMLIV MMMDXCII
LXIII A. 53 B. 63 C. 113 Click on the number that matches the Roman Numeral
You are correct! LXIII = 50+10+3 = 63 Remember: L= 50; X=10; III=3
DCXXIV A. 624 B. 1624 C. 5524 Click on the number that matches the Roman Numeral
You are correct! DCXXIV = 500 + 100 + 20 + 4 = 624
CCL A. 150 B. 250 C. 550 Click on the number that matches the Roman Numeral
You are correct! CCL = 100 + 100 + 50 = 250
Roman vs. Indo-Arabic Numerals • Indo-Arabic Numerals are the numbers that we use today. • 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 • Roman Numerals are used today, but not in everyday writing. • I, V, X, L, C, D, M • Roman Numerals don’t have a symbol for zero.
Adding Roman Numerals • Write down the two numbers you are adding right next to each other • Rearrange the letters so they start with the largest and end with the smallest. • Then start combining similar letters. • Check your answer by adding the Indo-Arabic numbers.
Adding Roman Numerals 23 + 58
Adding Roman Numerals Step 1. 23 + 58 Step 2. XXIII + LVIII Step 3. XXIIILVIII Step 4. LXXVIIIIII Step 4. IIIIII = VI Step 5. LXXVVI Step 6. VV = X Step 7. LXXXI = 81 Step 8. 23 + 58 = 81
Adding Roman Numerals • 1. 10 + 15 • 2. 225 + 130 • 3. 5 + 4 • 4. 100 + 215 • 5. 30 + 50 • 6. 100 + 200
Counting and Arithmetic • Decimal or base 10 number system • Origin: counting on the fingers • “Digit” from the Latin word digitus meaning “finger” • Base: the number of different digits including zero in the number system • Example: Base 10 has 10 digits, 0 through 9 • Binary or base 2: 2 digits, 0 and 1 • Octal or base 8:8 digits, 0 through 7 • Hexadecimal or base 16:16 digits, 0 – 9 and A – F
Decimal, Binary, Octal, Hexadecimal • Binary (base 2) • The number system is used directly by computers • Hexadecimal (base 16) • The number system that is used by computers to communicate with programmers eg colouring of webpages • Octal (base 8) • The number system that is used by either human or by computers to communicate with programmers • Decimal (base 10) • The number system that we are using
Decimal Binary Octal Hexadecimal 0 0 0 0 1 1 1 1 2 10 2 2 3 11 3 3 4 100 4 4 5 101 5 5 6 110 6 6 7 111 7 7 8 1000 10 8 9 1001 11 9 10 1010 12 A 11 1011 13 B 12 1100 14 C 13 1101 15 D 14 1110 16 E 15 1111 17 F
Why Binary? • Early computer design used decimal • John von Neumann proposed binary data processing (1945) • Simplified computer design • Used for both instructions and data
Numbers: Physical Representation • Different numerals, same number of oranges • Cave dweller: IIIII • Roman: V • Arabic: 5 • Different bases, same number of oranges • 510 • 1012 • 114
Number System • Roman: position independent • Modern: based on positional notation (place value) • Decimal system: system of positional notation based on powers of 10. • Binary system: system of positional notation based on powers of 2 • Octal system: system of positional notation based on powers of 8 • Hexadecimal system: system of positional notation based on powers of 16
10’s place 1’s place Positional Notation: Base 10 43 = 4 × 101 + 3 × 100 43
100’s place 10’s place 1’s place Positional Notation: Base 10 527 = 5 × 102 + 2 × 101 + 7 × 100 527
1’s place 64’s place 8’s place Positional Notation:Octal =40410 6248 404
4,096’s place 1’s place 16’s place 256’s place Positional Notation: Hexadecimal =26,37210 6,70416 26372
4,096’s place 1’s place 16’s place 256’s place Positional Notation: Hexadecimal =69310 2B516 693
Positional Notation: Binary 110101102 = 21410
Converting from Base 10 Power
22 Base 10to Base 2 2210 = 101102 Power 2 6 5 4 3 1 0 Base 32 2 64 16 8 4 2 1 Binary 1 0 1 1 0 Integer 0/1 2/2 6/8 6/4 22/16 Remainder 0 0 6 6 2
Remainder Quotient 22 Base 10to Base 2 Base 10 22 2 ) 22 ( 0 2 ) 11 ( 1 2 ) 5 ( 1 2 ) 2 ( 0 2 ) 1 ( 1 0 Base 2 10110
42 Base 10to Base 2 4210 = 1010102 Power 6 5 4 3 2 1 0 Base 32 2 64 16 8 4 2 1 Binary 1 0 1 0 1 0 Integer 0/1 2/2 10/8 2/4 10/16 42/32 Remainder 0 0 10 10 2 2
Remainder Quotient 42 Base 10to Base 2 Base 10 42 2 ) 42 ( 0 2 ) 21 ( 1 2 ) 10 ( 0 2 ) 5 ( 1 2 ) 2 ( 0 1 Base 2 101010
Addition in Binary Carry 1 0 1 0 + 1 0 1 0 ––––––––– 1 1 0 0 1 0
Multiplication in Binary 1 1 × 1 1 ––––– 1 1 + 1 1 0 –––––– 1 0 1 1 0
Remainder Quotient 126 Base 10to Base 8 Base 10 126 8 ) 126 ( 6 8 ) 15 ( 7 8 ) 1 ( 1 Base 8 176 0
Remainder Quotient 126 Base 10to Base 16 Base 10 126 16 ) 126 ( 14 E 8 ) 7 ( 7 0 Base 16 7E