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Learn to find and prove measures of inscribed angles in chapter 10-4, exploring various properties of circles, polygons, and parallel lines. Includes proofs and exercises for students.
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Inscribed Angles Chapter 10-4
Find measures of inscribed angles. • Find measures of angles of inscribed polygons. • intercepted Standard 7.0Students prove and use theorems involving the properties of parallel lines cut by a transversal, the properties of quadrilaterals, and the properties of circles. (Key) Standard 21.0Students prove and solve problems regarding relationships among chords, secants, tangents, inscribed angles, and inscribed and circumscribed polygons of circles. (Key) Lesson 4 MI/Vocab
Inscribed Angles Def: An angle whose vertex is on a circle and whose sides contain chords • The arc that lies in the interior of an inscribed angle and has endpoints on the angle is called the Intercepted Arc of the angle
Y X Inscribed Angles • The measure of an inscribed angle is one half of its intercepted arc. X = ½ Y Y = 2X
a a 108 Measures of Inscribed Angles 20 40 20 + 40 + a + 108 + a = 360 2a + 168 = 360 2a = 192 a = 96 Lesson 4 Ex1
108 Measures of Inscribed Angles 20 40 m1 = m2 = m3 = m4 = m5 = 96 96 180 – (20 + 54) = 106 Lesson 4 Ex1
A • B • C • D A. 30 B. 60 C. 15 D. 120 Lesson 4 CYP1
A • B • C • D A. 110 B. 55 C. 125 D. 27.5 Lesson 4 CYP1
A • B • C • D A. 30 B. 80 C. 40 D. 10 Lesson 4 CYP1
A • B • C • D A. 110 B. 55 C. 125 D. 27.5 Lesson 4 CYP1
A • B • C • D A. 110 B. 55 C. 125 D. 27.5 Lesson 4 CYP1
Inscribed Angles • If two inscribed angles of a circle intercept the same arc (or arcs), then the angles are . X Y mX = m Y
Given: Proof with Inscribed Angles Prove:ΔPJKΔEHG
Proof: Statements Reasons 1. 1. Given 2. If 2 chords are , corr. minor arcs are . 2. 3. Definition of intercepted arc 3. 4. 4. Inscribed angles of arcs are . 5. 5.Right angles are congruent. 6. ΔPJK ΔEHG 6.AAS Proof with Inscribed Angles Lesson 4 Ex2
Given: Choose the best reason to complete the following proof. Prove:ΔCEMΔHJM Lesson 4 CYP2
Proof: Statements Reasons 1. 2. 3. 4. 5. ΔCEMΔHJM 1. Given 2. ______ 3. Vertical angles are congruent. 4. Radii of a circle are congruent. 5.ASA • Alternate Interior Angle Theorem • Substitution C. Definition of angles D. Inscribed angles of arcs are . Lesson 4 CYP2
Inscribed Arcs and Probability This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. Lesson 4 Ex3
The probability that is the same as the probability of L being contained in . Inscribed Arcs and Probability This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. Lesson 4 Ex3
A. B. C.D. • A • B • C • D This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. Lesson 4 CYP3
A C B Inscribed Angles • A 90o inscribed angle intercepts a 180o arc • C is a right AB is a diameter of the circle R = 2.5 5 3 4
A • B • C • D A. 45 B. 90 C. 180 D. 80 Lesson 4 CYP4
A • B • C • D A. 17 B. 76 C. 60 D. 42 Lesson 4 CYP4
A • B • C • D A. 17 B. 76 C. 60 D. 42 Lesson 4 CYP4
A • B • C • D A. 73 B. 30 C. 60 D. 48 Lesson 4 CYP4
Inscribed Polygons • Reminder: If all the vertices of a polygon lie on the circle • The polygon is inscribed in the circle • The circle is circumscribed about the polygon • A quadrilateral can be inscribed in a circle its opposite angles are supplementary • Supplementary—adds up to 180o
Inscribed Polygons (3x + 2) + (2x –7) =180 5x – 5 = 180 5x = 185 x = 37 3x + 2 2x-7
Angles of an Inscribed Quadrilateral Draw a sketch of this situation. Lesson 4 Ex5
To find we need to know To find first find Angles of an Inscribed Quadrilateral Inscribed Angle Theorem Sum of arcs in circle=360 Subtract 174 from each side. Lesson 4 Ex5
Angles of an Inscribed Quadrilateral Inscribed Angle Theorem Substitution Divide each side by 2. Since we now know three angles of a quadrilateral, we can easily find the fourth. mQ + mR + mS + mT = 360 360° in a quadrilateral 87 + 102 + 93 + mT = 360 Substitution mT = 78 Subtraction Answer:mS = 93; mT = 78 Lesson 4 Ex5
A • B • C • D A. 99 B. 104 C. 81 D. 76 Lesson 4 CYP5
A • B • C • D A. 99 B. 104 C. 81 D. 76 Lesson 4 CYP5
Homework Chapter 10-4 • Pg 583 6 – 8, 15 – 21, 24 – 31 all