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Example 2 Find

Example 2 Find Solution For 0  x  3 , G(x) is the shaded green area in the left diagram. Hence G(x) is the area of the quarter circle of radius 3 minus the area of the

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Example 2 Find

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  1. Example 2 Find Solution For 0  x  3, G(x) is the shaded green area in the left diagram. Hence G(x) is the area of the quarter circle of radius 3 minus the area of the yellow shaded region R in the right diagram above. Observe that Hence the area of R is the area of the sector of angle  minus the area of the right triangle OPQ: Then G(0) = 0 and for 0<x 3: 

  2. For -3x<0, G(x) is related to the area of the shaded pink region above which by symmetry is the same as the area of the shaded green region G(-x) which we computed on the first slide. Observe that G(x) is given by different formulas for -3x<0 and for 0<x 3.

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