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Ethenol Ethanal Equilibrium . Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M. Trial 1 equilibrium: [al] = 8 mol/1 L = 8 M [ol] = 2 mol/1 L = 2 M. al. ol. Ethenol Ethanal Equilibrium . Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M.
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Ethenol Ethanal Equilibrium Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M Trial 1 equilibrium: [al] = 8 mol/1 L = 8 M [ol] = 2 mol/1 L = 2 M al ol
Ethenol Ethanal Equilibrium Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M Trial 1 equilibrium: [al] = 8 mol/1 L = 8 M [ol] = 2 mol/1 L = 2 M al ol Trial 2 initially: [al] = 0 [ol] =10 mol/ 0.5 L = 20 M Trial 2 equilibrium: [al] = 8 mol/ 0.5 L = 16 M [ol] = 2 mol/ 0.5 L = 4 M
Ethenol Ethanal Equilibrium Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M Trial 1 equilibrium: [al] = 8 mol/1 L = 8 M [ol] = 2 mol/1 L = 2 M al ol Trial 2 initially: [al] = 0 [ol] =10 mol/ 0.5 L = 20 M Trial 2 equilibrium: [al] = 8 mol/ 0.5 L = 16 M [ol] = 2 mol/ 0.5 L = 4 M Trial 3 initially: [al] = 20 mol/1 L = 20 M [ol] = 20 mol/1 L = 20 M Trial 3 equilibriuim: [al] = 32 mol/1 L = 32 M [ol] = 8 mol/1 L = 8 M For each trial, [al]/[ol] = 4 when equilibrium is reached. The ratio is constant from one trial to the next. Ethanal is more stable than ethenol.
Ethenol Ethanal Equilibrium Trial 1 initially: [al] = 0 [ol] = 10 mol/1 L = 10 M Trial 1 equilibrium: [al] = 8 mol/1 L = 8 M [ol] = 2 mol/1 L = 2 M al ol Trial 2 initially: [al] = 0 [ol] =10 mol/ 0.5 L = 20 M Trial 2 equilibrium: [al] = 8 mol/ 0.5 L = 16 M [ol] = 2 mol/ 0.5 L = 4 M Trial 3 initially: [al] = 20 mol/1 L = 20 M [ol] = 20 mol/1 L = 20 M Trial 3 equilibriuim: [al] = 32 mol/1 L = 32 M [ol] = 8 mol/1 L = 8 M Trial 4 intermediate time Trial 4 initially: [al] = 40 mol/1 L = 40 M [ol] = 0 Trial 4 equilibriuim: [al] = 32 mol/1 L = 32 M [ol] = 8 mol/1 L = 8 M For each trial, [al]/[ol] = 4 when equilibrium is reached. The ratio is constant from one trial to the next. Ethanal is more stable than ethenol.