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9.1 Square Roots

9.1 Square Roots. SQUARE ROOT OF A NUMBER If b 2 = a, then b is a square root of a . Examples: 3 2 = 9, so 3 is a square root of 9. (-3) 2 = 9, so -3 is a square root of 9. Chapter 9 Test Review. Evaluate the expression. - . Chapter 9 Test Review. Evaluate the expression.

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9.1 Square Roots

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  1. 9.1 Square Roots SQUARE ROOT OF A NUMBER If b2 = a, then b is a square root of a. Examples:32= 9, so 3 is a square root of 9. (-3)2= 9, so -3 is a square root of 9.

  2. Chapter 9 Test Review Evaluate the expression. -

  3. Chapter 9 Test Review Evaluate the expression.

  4. Chapter 9 Test Review Evaluate the expression.

  5. Chapter 9 Test Review Evaluate the expression. -

  6. 9.2 Solving Quadratic Equations by Finding Square Roots QUADRATIC EQUATION When b = 0, this equation becomes ax2 + c = 0. One way to solve a quadratic equation of the form ax2+ c = 0 is to isolate the x2 on one side of the equation. Then find the square root(s) of each side.

  7. Chapter 9 Test Review Solve the equation. x2 = 144

  8. Chapter 9 Test Review Solve the equation. 8x2= 968

  9. Chapter 9 Test Review Solve the equation. 5x2 – 80 = 0

  10. Chapter 9 Test Review Solve the equation. 3x2 – 4 = 8

  11. 9.3 Simplifying Radicals PRODUCT PROPERTY OF RADICALS = EXAMPLE: = = = 2

  12. Chapter 9 Test Review Simplify the expression.

  13. Chapter 9 Test Review Simplify the expression.

  14. Chapter 9 Test Review Simplify the expression.

  15. Chapter 9 Test Review Simplify the expression.

  16. 9.5 Solving Quadratic Equations by Graphing The x-intercepts of graphy = ax2 + bx + c are the solutions of the related equations ax2 + bx + c = 0. Recall that an x-intercept is the x-coordinate of a point where a graph crosses the x-axis. At this point, y = 0.

  17. Chapter 9 Test Review Use a graph to estimate the solutions of the equation. Check your solutions algebraically. x2 – 3x = -2

  18. Chapter 9 Test Review Use a graph to estimate the solutions of the equation. Check your solutions algebraically. -x2 + 6x = 5

  19. Chapter 9 Test Review Use a graph to estimate the solutions of the equation. Check your solutions algebraically. x2 – 2x = 3

  20. 9.6 Solving Quadratic Equations by the Quadratic Formula The solutions of the quadratic equation ax2 + bx + c = 0 are: x = when a ≠ 0 and b2 – 4ac > 0. THE QUADRATIC FORMULA

  21. Chapter 9 Test Review Use the quadratic formula to solve the equation. 3x2 – 4x + 1 = 0

  22. Chapter 9 Test Review Use the quadratic formula to solve the equation. -2x2 + x + 6 = 0

  23. Chapter 9 Test Review Use the quadratic formula to solve the equation. 10x2– 11x + 3 = 0

  24. 9.7 Using the Discriminant In the quadratic formula, the expression inside the radical is the DISCRIMINANT. x = DISCRIMINANT - 4ac

  25. Chapter 9 Test Review Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution. 3x2 – 12x + 12 =0

  26. Chapter 9 Test Review Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution. 2x2 + 10x + 6=0

  27. Chapter 9 Test Review Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution. -x2 + 3x - 5 =0

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