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ME 4611: Experiment 5 Bomb Calorimeter Experiment

ME 4611: Experiment 5 Bomb Calorimeter Experiment. Yvette Triay - Leader Group 4. Purpose of the Experiment. To understand what a bomb calorimeter is, how to use it, and why it is useful To determine the thermal capacitance of the calorimeter

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ME 4611: Experiment 5 Bomb Calorimeter Experiment

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  1. ME 4611: Experiment 5Bomb Calorimeter Experiment Yvette Triay - Leader Group 4

  2. Purpose of the Experiment • To understand what a bomb calorimeter is, how to use it, and why it is useful • To determine the thermal capacitanceof the calorimeter • To determine the gross heat of combustionof the samples provided

  3. What is a bomb-calorimeter? • Used to measure heat created by a sample burned under an oxygen atmosphere in a closed vessel, which is surrounded by water • Temperature differences in water are measured • Thermal capacitance and heat of combustions can be calculated with this data

  4. Equipment:Parr Oxygen Bomb Calorimeter Picture taken from Parr Operating Manual: 1341 Oxygen Bomb Calorimeter [4]

  5. Picture taken from Parr Operating Manual: 1341 Oxygen Bomb Calorimeter [4]

  6. Thermodynamic Background 1st Law of Thermodynamics Q=mcvΔT Q – heat of combustion mcv – thermal capacitance of the system ΔT – temperature rise

  7. 2 Tests Conducted 1) Known Fuel (Benzoic Acid) 2) Unknown Fuel Calorimeter capacitance remains constant Find heat of combustion Q=(mcv)calorimeterΔT • Calorimeter is considered the thermodynamic system • Find thermal capacitance (mcv)calorimeter=Q/ΔT ★Q is the heat of combustion of the fuel and the ignition wire.

  8. Estimate the thermal capacitance of the system (2kg water and 3 kg stainless steel). (Thermal Capacitance)system = m(H2O)cv(H2O) + m(SS)cv(SS) (mcv)System = (2 kg)(4180*J/kg-K) + (3 kg)(470*J/kg-K) (mcv)System = 9770 J/K * See [1] of Appendices

  9. Predict the temperature rise for 1 gram of Benzoic acid, which will be used as the calibration sample. Using Q = 26414*J/g [1], and plugging into the equation ΔT = Q/mcv ΔT = (26414 J/g)*(1 g) / (9770 J/K) ΔT = 2.7 K * See [2] of Appendices

  10. Appendices[1] Cengal, Yunus. Heat and Mass Transfer: Fundamentals & Application, 4th Ed.[2] http://www2.stetson.edu/~wgrubbs/datadriven/fchen/strain/strainchen.html[3] ME 4611 Laboratory Manual: Experiment 5 – Bomb Calorimeter Experiment[4] Parr Operating Manual: 1341 Oxygen Bomb Calorimeter [5] 1st Law of Thermodynamics: (total energy entering a system ) – (total energy leaving a system) = (change in total energy of the system)

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