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EOT2 EOT1? EOT. Empirical Methods in Short-Term Climate Prediction Huug van den Dool Price: £49.95 (Hardback) ISBN-10: 0-19-920278-8 ISBN-13: 978-0-19-920278-2 Estimated publication date: November 2006 Oxford University Press.
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Empirical Methods in Short-Term Climate Prediction Huug van den Dool Price: £49.95 (Hardback)ISBN-10: 0-19-920278-8ISBN-13: 978-0-19-920278-2Estimated publication date: November 2006 Oxford University Press Foreword , Professor Edward Lorenz (Massachusetts Institute of Technology) Preface 1. Introduction 2. Background on orthogonal functions and covariance 3. Empirical wave propagation 4. Teleconnections 5. Empirical orthogonal functions 6. Degrees of freedom 7. Analogues 8. Methods in short-term climate prediction 9. The practice of short-term climate prediction 10. Conclusion References Index
Chapter 8. Methods in Short-Term Climate Prediction 1218.1 Climatology 1228.2 Persistence 1248.3 Optimal climate normals 1268.4 Local regression 1298.5 Non-local regression and ENSO 1358.6 Composites 1388.7 Regression on the pattern level 1398.7.1 The time-lagged covariance matrix 1398.7.2 CCA, SVD and EOT2 1418.7.3 LIM, POP and Markov 1458.8 Numerical methods 1468.9 Consolidation 1478.10 Other methods 1498.11 Methods not used 151Appendix 1: Some practical space–time continuity requirements 152Appendix 2: Consolidation by ridge regression 153
EOT-normal Q is diagonalized Qa is not diagonalized (1) is satisfied with αm orthogonal Q tells about Teleconnections Matrix Q with elements: qij=∑ f(si,t)f(sj,t) t iteration Rotation EOF Both Q and Qa Diagonalized (1) satisfied – Both αm and em orthogonal αm (em) is eigenvector of Qa(Q) Laudable goal: f(s,t)=∑ αm(t)em(s) (1) m Discrete Data set f(s,t) 1 ≤ t ≤ nt ; 1 ≤ s ≤ ns Arbitrary state Rotation iteration Matrix Qa with elements: qija=∑f(s,ti)f(s,tj) s EOT-alternative Q is not diagonalized Qa is diagonalized (1) is satisfied with em orthogonal Qa tells about Analogues Fig.5.6: Summary of EOT/F procedures.
EOT-normal Q is diagonalized Qa is not diagonalized (1) is satisfied with αm orthogonal Q tells about Teleconnections Matrix Q with elements: qij=∑ f(si,t)f(sj,t) t iteration Rotation EOF Both Q and Qa Diagonalized (1) satisfied – Both αm and em orthogonal αm (em) is eigenvector of Qa(Q) Laudable goal: f(s,t)=∑ αm(t)em(s) (1) m Discrete Data set f(s,t) 1 ≤ t ≤ nt ; 1 ≤ s ≤ ns iteration Arbitrary state Rotation Iteration (as per power method) Matrix Qa with elements: qija=∑f(s,ti)f(s,tj) s EOT-alternative Q is not diagonalized Qa is diagonalized (1) is satisfied with em orthogonal Qa tells about Analogues Fig.5.6: Summary of EOT/F procedures.
Fig. 4.3 EV(i),the variance explained by single gridpoints in % of the total variance, using equation 4.3. In the upper left for raw data, in the upper right after removal of the first EOT mode, lower left after removal of the first two modes. Contours every 4%. The timeseries shown are the residual height anomaly at the gridpoint that explains the most of the remaining domain integrated variance.
Fig.4.4 Display of four leading EOT for seasonal (JFM) mean 500 mb height. Shown are the regression coefficient between the height at the basepoint and the height at all other gridpoints (maps) and the timeseries of residual 500mb height anomaly (geopotential meters) at the basepoints. In the upper left for raw data, in the upper right after removal of the first EOT mode, lower left after removal of the first two modes. Contours every 0.2, starting contours +/- 0.1. Data source: NCEP Global Reanalysis. Period 1948-2005. Domain 20N-90N
Fig.5.4 Display of four leading alternative EOT for seasonal (JFM) mean 500 mb height. Shown are the regression coefficient between the basepoint in time (1989 etc) and all other years (timeseries) and the maps of 500mb height anomaly (geopotential meters) observed in 1989, 1955 etc . In the upper left for raw data, in the upper right after removal of the first EOT mode, lower left after removal of the first two modes. A postprocessing is applied, see Appendix I, such that the physical units (gpm) are in the time series, and the maps have norm=1. Contours every 0.2, starting contours +/- 0.1. Data source: NCEP Global Reanalysis. Period 1948-2005. Domain 20N-90N
Fig 5.7. Explained Variance (EV) as a function of mode (m=1,25) for seasonal mean (JFM) Z500, 20N-90N, 1948-2005. Shown are both EV(m) (scale on the left, triangles) and cumulative EV(m) (scale on the right, squares). Red lines are for EOF, and blue and green for EOT and alternative EOT respectively.
EOT2 (1) and (2) satisfied αm and βm orthogonal (homo-and-heterogeneous Cff (τ=0), Cgg(τ=0) and Cfg diagonalized One time series, two maps. CCA Very close to EOT2, but two, maximally correlated, time series. Cross Cov Matrix Cfgwith elements: cij= ∑ f(si,t)g(sj,t+ τ)/nt t Laudable goals: f(s,t) = ∑ αm(t)em(s) (1) m g(s,t +τ) = ∑ βm(t +τ)dm(s) (2) m constrained by a connection between α and β and/or e and d. Discrete Data set f(s,t) 1 ≤ t ≤ nt ; 1 ≤ s ≤ ns Discrete Data set g(s,t +τ) 1 ≤ t ≤ nt ; 1 ≤ s ≤ n’s Alt Cross Cov Matrix Cafgwith elements: caij= ∑ f(s,ti)g(s,tj+ τ)/ns s SVD Somewhat like EOT2a, but two maps, and (heterogeneously) orthogonal time series. EOT2-alternative (1) and (2) satisfied em and dm orthogonal αm and βm heterogeneously orthogonal Caff (τ=0), Cagg(τ=0) and Cafg diagonalized Two time series, one map. Fig.x.y: Summary of EOT2 procedures.
EOT2 (1) and (2) satisfied αm and βm orthogonal Cff (τ=0), Cgg(τ=0) and Cfg diagonalized One time series, two maps. CCA Very close to EOT2, but two, maximally correlated, time series. Cross Cov Matrix Cfgwith elements: cij= ∑ f(si,t)g(sj,t+ τ)/nt t Laudable goals: f(s,t) = ∑ αm(t)em(s) (1) m g(s,t +τ) = ∑ βm(t +τ)dm(s) (2) m Constrained by a connection between α and β and/or e and d. Discrete Data set f(s,t) 1 ≤ t ≤ nt ; 1 ≤ s ≤ ns Discrete Data set g(s,t +τ) 1 ≤ t ≤ nt ; 1 ≤ s ≤ n’s Alt Cross Cov Matrix Cafgwith elements: caij= ∑ f(s,ti)g(s,tj+ τ)/ns s SVD Somewhat like EOT2a, but two maps, and (heterogeneously) orthogonal time series. EOT2-alternative (1) and (2) satisfied em and dm orthogonal Caff (τ=0), Cagg(τ=0) and Cafg diagonalized Two time series, one map. Fig.x.y: Summary of EOT2 procedures.
CCA: • Make a square M = Qf-1 Cfg Qg-1 CfgT • E-1 M E =diag ( λ1 ,λ2, λ3,… λM) • cor(m)=sqrt (λm) SVD: 1) UT Cfg V =diag (σ1 , σ2, … , σm) Explained Squared Covariance = σ2m • Assorted issues: • Prefiltering f and g , before calculating Cfg • Alternative approach complicated when domains for f and g don’t match • Iteration and rotation: CCA > EOT2-normal; SVD > EOT2-alternative ???
Keep in mind • EV (EOF/EOT) and EOT2 • Squared covariance (SC) in SVD • SVD singular vectors of C • CCA eigenvectors of M • LIM complex eigenvectors of L (close to C) • MRK no modes are calculated (of L)
T-obs T-CA diff 1991-2006 .52C .10C .42C 100.00% (all gridpoints north of 20N and anomalies relative to 61-90.) We are warmer by 0.52C, and the circulation explains only 0.10. So has T850 risen 0.42 ±error due to factor X ??? The plain difference CA minus Obs has a problem, namely that CA (like a regression) 'damps'. (The degree of damping is related to the success of the specification as measured by a correlation). Obs minus CA thus tends to have the sign of the observed anomaly (which is warm these days). A reasonable explanatory equation reads : T_obs = T_CA * 1/d + delta, where delta is the true temperature change we are seeking and the 1/d factor undoes the damping of the specification method.
Two unknowns (d(amping) and delta), and I make two equations by doing an averaging separately for gridpoints where T850 was observed above (62.5% of the cases in Jan) and below the mean (37.5%). (This is a shortcut for a regression thru thousands of points (years times gridpoints))/ For instance, in January we find: T-obs T-CA diff 1991-2006 1.65C .82C .83C 62.53% (at points where T-obs anomaly is positive) 1991-2006 -1.35C -1.09C -.26C 37.47% (at points where T-obs anomaly is negative) Notice that cold anomalies, although covering less area, are also damped. I assume that damping (d; 0<d<1) is the same for cold and warm anomalies. Substituting the T-obs and T-CA twice we get two equations and find (for January): damp= 0.64 and delta=0.37
I am now building a Table as follows: Month Damping Delta 1 0.64 0.37 2 0.67 0.27 3 0.67 0.33 4 0.58 0.15 5 0.57 0.19 6 0.56 0.31 7 0.48 0.33 8 0.50 0.22 9 (sep) 0.51 0.47