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Solve systems of linear inequalities.

Objective. Solve systems of linear inequalities. Vocabulary. system of linear inequalities. When a problem uses phrases like “greater than” or “no more than,” you can model the situation using a system of linear inequalities.

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Solve systems of linear inequalities.

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  1. Objective Solve systems of linear inequalities.

  2. Vocabulary system of linear inequalities

  3. When a problem uses phrases like “greater than” or “no more than,” you can model the situation using a system of linear inequalities. A system of linear inequalities is a set of two or more linear inequalities with the same variables. The solution to a system of inequalities is often an infinite set of points that can be represented graphically by shading. When you graph multiple inequalities on the same graph, the region where the shadings overlap is the solution region.

  4. y< – 3 y ≥–x + 2 For y < – 3, graph the dashed boundary line y =– 3, and shade below it. Example 1A: Graphing Systems of Inequalities Graph the system of inequalities. For y ≥ –x + 2, graph the solid boundary line y = –x + 2, and shade above it. The overlapping region is the solution region.

  5. Example 1B: Graphing Systems of Inequalities Graph each system of inequalities. y< –3x + 2 y ≥ –1 For y < –3x + 2, graph the dashed boundary line y =–3x + 2, and shade below it. For y ≥–1, graph the solid boundary line y =–1, and shade above it.

  6. Example 2: Art Application Lauren wants to paint no more than 70 plates for the art show. It costs her at least $50 plus $2 per item to produce red plates and $3 per item to produce gold plates. She wants to spend no more than $215. Write and graph a system of inequalities that can be used to determine the number of each plate that Lauren can make.

  7. Example 2 Continued Let x represent the number of red plates, and let y represent the number of gold plates. The total number of plates Lauren is willing to paint can be modeled by the inequality x + y ≤ 70. The amount of money that Lauren is willing to spend can be modeled by 50 + 2x + 3y ≤ 215. x 0 y 0 The system of inequalities is . x + y ≤ 70 50 + 2x + 3y ≤ 215

  8. Example 2 Continued Graph the solid boundary line x + y = 70, and shade below it. Graph the solid boundary line 50 + 2x + 3y ≤ 215, and shade below it. The overlapping region is the solution region.

  9. Check It Out! Example 2 Leyla is selling hot dogs and spicy sausages at the fair. She has only 40 buns, so she can sell no more than a total of 40 hot dogs and spicy sausages. Each hot dog sells for $2, and each sausage sells for $2.50. Leyla needs at least $90 in sales to meet her goal. Write and graph a system of inequalities that models this situation.

  10. Check It Out! Example 2 Continued Let d represent the number of hot dogs, and let s represent the number of sausages. The total number of buns Leyla has can be modeled by the inequality d + s ≤ 40. The amount of money that Leyla needs to meet her goal can be modeled by 2d + 2.5s ≥ 90. d 0 s 0 The system of inequalities is . d + s ≤ 40 2d + 2.5s ≥ 90

  11. Check It Out! Example 2 Continued Graph the solid boundary line d + s = 40, and shade below it. Graph the solid boundary line 2d + 2.5s ≥ 90, and shade above it. The overlapping region is the solution region.

  12. Systems of inequalities may contain more than two inequalities.

  13. Example 3: Geometry Application Graph the system of inequalities, and classify the figure created by the solution region. x ≥ –2 x ≤ 3 y ≥ –x + 1 y ≤ 4

  14. Example 3 Continued Graph the solid boundary line x = –2 and shade to the right of it. Graph the solid boundary line x = 3, and shade to the left of it. Graph the solid boundary line y = –x + 1, and shade above it. Graph the solid boundary line y = 4, and shade below it. The overlapping region is the solution region.

  15. Check It Out! Example 3a Graph the system of inequalities, and classify the figure created by the solution region. x ≤ 6 y ≤ x + 1 y ≥ –2x + 4

  16. Graph the solid boundary line x = 6 and shade to the left of it. Graph the solid boundary line, y ≤x + 1 and shade below it. Graph the solid boundary line y ≥ –2x + 4, and shade below it. The overlapping region is the solution region. The solution is a triangle. Check It Out! Example 3a Continued

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