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10.7 Areas of Circles and Sectors

10.7 Areas of Circles and Sectors. Geometry. Objectives/DFA/HW. Objectives You will find the areas circles and sectors of circles. DFA• DFA pp663 #24 HW Assignment : pp. 663-665 (2-46 even). Examples of regular polygons inscribed in circles. 4 -gon. 3 -gon. 5 -gon. 6 -gon.

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10.7 Areas of Circles and Sectors

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  1. 10.7 Areas of Circles and Sectors Geometry

  2. Objectives/DFA/HW • Objectives • You will find the areas circles and sectors of circles. • DFA• • DFA pp663 #24 • HW • Assignment: pp. 663-665 (2-46 even)

  3. Examples of regular polygons inscribed in circles. 4 -gon 3 -gon 5 -gon 6 -gon

  4. Theorem. 11.7: Area of a Circle • The area of a circle is  times the square of the radius or A = r2.

  5. Ex. 1: Using the Area of a Circle • Find the area of P. Solution: • Use r = 8 in the area formula. A = r2 =  • 82 = 64  201.06 • So, the area if 64, or about 201.06 square inches.

  6. Ex. 1: Using the Area of a Circle • Find the diameter of Z. Solution: • Area of circle Z is 96 cm2. A = r2 96=  r2 96= r2  30.56  r2 5.53  r • The diameter of the circle is about 11.06 cm.

  7. More . . . • A sector of a circle is a region bounded by two radii of the circle and their intercepted arc. In the diagram, sector APB is bounded by AP, BP, and . The following theorem gives a method for finding the area of a sector.

  8. Theorem 11.8: Area of a Sector • The ratio of the area A of a sector of a circle to the area of the circle is equal to the ratio of the measure of the intercepted arc to 360°. m m A = or A = • r2 r2 360° 360°

  9. Ex. 2: Finding the area of a sector • Find the area of the sector shown below. Sector CPD intercepts an arc whose measure is 80°. The radius is 4 ft. m A = • r2 360°

  10. m A = • r2 360° 80° = • r2 360° Ex. 2 Solution Write the formula for area of a sector. Substitute known values. Use a calculator.  11.17 • So, the area of the sector is about 11.17 square feet.

  11. Ex. 3: Finding the Area of a Sector • A and B are two points on a P with radius 9 inches and mAPB = 60°. Find the areas of the sectors formed by APB. FIRST draw a diagram of P and APB. Shade the sectors. LABEL point Q on the major arc. FIND the measures of the minor and major arcs. 60°

  12. 60° = • r2 360° Ex. 3: Finding the Area of a Sector • Because mAPB = 60°, m = 60° and • m = 360° - 60° = 300°. Use the formula for the area of a sector. Area of small sector 60° = •  • 92 360° 1 = •  • 81 6  42.41 square inches

  13. Ex. 3: Finding the Area of a Sector • Because mAPB = 60°, m = 60° and • m = 360° - 60° = 300°. Use the formula for the area of a sector. 300° Area of large sector = • r2 360° 60° = •  • 92 360° 5 = •  • 81 6  212.06 square inches

  14. Using Areas of Circles and regions • You may need to divide a figure into different regions to find its area. The regions may be polygons, circles, or sectors. To find the area of the entire figure, add or subtract the areas of separate regions as appropriate.

  15. Ex. 4: Find the Area of a Region • Find the area of the region shown. The diagram shows a regular hexagon inscribed in a circle with a radius of 5 meters. The shaded region is the part of the circle that is outside the hexagon. Area of Circle Area of Hexagon Area of Shaded =

  16. Solution: Area of Circle Area of Hexagon Area of Shaded = = r2 ½ aP = ( • 52 ) – ½ • ( √3) • (6 • 5) 75 = 25 - √3, or about 13.59 square meters. 2

  17. Ex. 5: Finding the Area of a Region • Woodworking. You are cutting the front face of a clock out of wood, as shown in the diagram. What is the area of the front of the case?

  18. Ex. 5: Finding the Area of a Region

  19. More . . . • Complicated shapes may involve a number of regions. In example 6, the curved region is a portion of a ring whose edges are formed by concentric circles. Notice that the area of a portion of the ring is the difference of the areas of the two sectors.

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