1 / 11

Geo CP Day 25 > 2-4 Special Pairs of Angles

Geo CP Day 25 > 2-4 Special Pairs of Angles > SWBAT def. and id complementary, supplementary and vertical angles. Pg. 52: 1,2,3,5,8,9,10, 13-18, 19,20, 22,,25,27,29. D. A. B. 2. 3. M. 1. 4. C. Special Angles: Vertical Angles: m<1 = m<3 or m<2 = m<4

dezso
Download Presentation

Geo CP Day 25 > 2-4 Special Pairs of Angles

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Geo CP Day 25 >2-4 Special Pairs of Angles >SWBAT def. and id complementary, supplementary and vertical angles. Pg. 52: 1,2,3,5,8,9,10, 13-18, 19,20, 22,,25,27,29

  2. D A B 2 3 M 1 4 C • Special Angles: • Vertical Angles: m<1 = m<3 or m<2 = m<4 • Supplementary Angles: m<1 + m<2 = 180 or …

  3. D 2 A B 1 M C • Special Angles: • Complementary Angles: m<1 + m<2 = 90 • C goes to C and S goes to S

  4. B C A D M F E Given m<AMB = 40, m<DMC = 45 Find: m<AMC, m<CME, m<BME, m<FME

  5. D A B 2 3 1 4 C m<2 = 3x + 10, m<1 = 2x + 20 Find m<3 and m<4

  6. B C A D M F E Given m<BMC = 90, m<DMC = 30 Find: m<AMB, m<CME, m<DMF, m<FMB

  7. D A B 2 3 1 4 C m<1 = 3x + 10, m<3 = 2x + 20 Find m<3 and m<4

  8. B C A D M F E Given m<EMC = 90, m<DMC = 30 Find: m<AMF, m<CMB, m<DMF, m<DMB

  9. Two angles are complementary. The first equals 2x + 5 the second equals 6x + 5. What are the measures of the two angles?

  10. B C A D M F E Given MD bisects <CME, m<BMA = 30 Find: m<AMF, m<CMB, m<DMF, m<DMB

  11. B C A D M F E Given MD bisects <CME, m<BMC = 100 Find: m<AMF, m<CMB, m<DMF, m<DMB

More Related