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Lim X 2 – 4X + 3 x 3 X 2 –X - 6. Solução 1. X 2 – 4X + 3 = (X-3)(X-1). X 2 –X - 6 = (X-3)(X+2). X 2 – 4X + 3 = (X-3)(X-1) = (X-1) X 2 –X - 6 (X-3)(X+2) (X+2). Substituindo X=3, teremos: Lim X2 – 4X + 3 = 3-1 = 2
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Lim X2 – 4X + 3 x 3 X2 –X - 6 Solução 1 X2 – 4X + 3 = (X-3)(X-1) X2 –X - 6 = (X-3)(X+2) X2 – 4X + 3 = (X-3)(X-1) = (X-1) X2 –X - 6 (X-3)(X+2) (X+2) Substituindo X=3, teremos: Lim X2 – 4X + 3 = 3-1 = 2 x 3 X2 –X – 6 3+2 5 Solução 2 X2 – 4X + 3 = 1 - 3X+9___= 1 - 3(X-3)_ = 1- __3__ X2 –X - 6 ( X-3)(x+2) ( X-3)(x+2) (X+2) Substituindo X=3, teremos: Lim X2 – 4X + 3 = 1- __3_= _2_ x 3 X2 –X – 6 5 5