400 likes | 617 Views
ECE 875: Electronic Devices. Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University ayresv@msu.edu. Lecture 16, 14 Feb 14. HW 04: FRI: Pr. 2.07 Chp. 02: pn junction: Experimental measurements for concentration: Hall effect – Chp. 01: material:
E N D
ECE 875:Electronic Devices Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University ayresv@msu.edu
Lecture 16, 14 Feb 14 • HW 04: FRI: Pr. 2.07 • Chp. 02: pn junction: • Experimental measurements for concentration: • Hall effect – Chp. 01: material: • measure VAB, and I, choose dimensions and Bext • C-V – Chp. 02: pn junction • Examples VM Ayres, ECE875, S14
Jgen = ? OR Jrec = ? Which: are you in forward or reverse bias? What happens to the depletion region WD? VM Ayres, ECE875, S14
1/tg = everything that’s left in U VM Ayres, ECE875, S14
Jgen-rec = q U length Jgen-rec = tg is given = 1 x 10-5 sec If: Assume: Si @ 300 K:
Lecture 16, 14 Feb 14 • HW 04: FRI: Pr. 2.07 • Chp. 02: pn junction: • Experimental measurements for concentration: • Hall effect – Chp. 01: material: • measure VAB, and I, choose dimensions and Bext • C-V – Chp. 02: pn junction • Examples VM Ayres, ECE875, S14
Remember this sequence in real research: find: • Charge Q and charge density r • Electric field E • Potential y • Energy barrier q y • Depletion region WD or equivalent local region • C-V • I-V
Abrupt junction: Q and r = Constant values E (x) yi(x) q yi(x)
For Abrupt junction: find: • Charge Q and charge density r • Electric field E • Potential y • Energy barrier q y
Charge density r = all relevant concentrations: VM Ayres, ECE875, S14
For Abrupt junction: find: • Charge Q and charge density r • Electric field E • Potential y • Energy barrier q y
Internal electric field E (x): must find separately on p-side and n-side: Note: Linear: VM Ayres, ECE875, S14
Internal electric field E (x): must find separately on p-side and n-side: VM Ayres, ECE875, S14
Internal electric field E (x): Note: Linear: VM Ayres, ECE875, S14
Solve for maximum value of E –field: VM Ayres, ECE875, S14
For Abrupt junction: find: • Charge Q and charge density r • Electric field E • Potential y • Energy barrier q y
Find: potential yi(x): (Practical: you may be able to measure a potential drop: yi(x2) - yi(x1) ) + Can integrate this! VM Ayres, ECE875, S14
Potential yi(x): must find separately on p-side and n-side: p-side of depletion region: VM Ayres, ECE875, S14
Potential yi(x): must find separately on p-side and n-side: n-side of depletion region: VM Ayres, ECE875, S14
Example: find the potential drop across the p-side of the depletion region VM Ayres, ECE875, S14
Answer: potential DROP: Eq’n (15a) VM Ayres, ECE875, S14
ybi is the potential drop across the whole depletion region – what you mainly measure. At least have an experimental estimate of Emax Can we say anything about this factor VM Ayres, ECE875, S14
ybi is the potential drop across the whole depletion region – what you mainly measure. You know how you doped NA and ND – but could have hidden impurities or a bad doping process WD = VM Ayres, ECE875, S14
An experimental measure for the Abrupt junction: C-V curve: VM Ayres, ECE875, S14
Useful parts on C-V graph: slope concentration N intercept equilibrium potential ybi 0 V = Vbattery VM Ayres, ECE875, S14
The 2 x kT/q correction factor: Shielding by neutral region electrons Shielding by neutral region holes VM Ayres, ECE875, S14
Example:(a) find the slope and set up the calculation for N(b) find the intercept and set up the calculation for ybi V = Vbattery
Linearly graded junction: power of x raised by 1: Q and r = linear = Constant x x E (x) yi(x) q yi(x)
Linearly graded junction: power of x raised by 1: r = linear = Constant “a” x x
An experimental measure for the linearly graded junction: C-V curve: Missing 2kT/q in (38) intercept Experimentally sweep this slope VM Ayres, ECE875, S14
Answer: Given: abrupt p+n junction