1 / 14

Теорема на Талес

Теорема на Талес. Теорема за ъглополовяща в триъгълник. Самостоятелна работа на IX “A” клас. Задача 1 А). Дадено : MN = 4 , BN = 9 , BN = MC Търсим : AN = ? , AB = ?, AC = ? Решение : Тр. ABC MN || BC ( M лежи на AC , N лежи на AD ) T AN/ NB = AM/MC x/9 =4/x X 2 = 36

dixie
Download Presentation

Теорема на Талес

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Теорема на Талес Теорема за ъглополовяща в триъгълник

  2. Самостоятелна работа на IX “A” клас

  3. Задача 1 А) • Дадено : • MN = 4 , BN = 9 , BN = MC • Търсим : • AN = ? , AB = ?, AC = ? • Решение : • Тр. ABC MN || BC ( M лежи на AC , N лежи на AD ) • TAN/ NB = AM/MC • x/9 =4/x • X2 = 36 • X = 6 • AN = 6 , AB = 15 , AC = 10

  4. Б) • Дадено : • AN : NB = 2 : 3, AB = 15 • Търсим : • AM , MC , AB = ? • Решение : • 2x + 3x = 15 5x=15 x = 3 • AN = 2.3 = 6 • NB = 3.3 = 9 • AN/AM = BN/MC 6/AM=9/MC MC/AM =9/6=3/2

  5. Задача 2 : • Дадено: • Тр. ABC , BC = 8 , CA = 6 , AB = 7 , CL =l ъгъл C • Т->CA/AL=CB/LB=6x=8/7-x • 42+6x+8x=0 • 14x=42 • X=42/14=3

  6. Задача 3: • Тр.ABC,cl=l+c • AL:LB=3:4 ,AB=7см.,AC=6см.,BC=?,P=?см. • 3x+4x=7x=7 • X=1 AL=3,BL=4,AC/AL=CB/BL, 6/3=x/4 • 3x=6.4 BC=8 3x=2.4=8 P тр.6+7+8=21см.

  7. Задача 4 : Тр.ABC AC=BC,Al=C ъгъл a; BC:AB=2:1 BC:AB=2:1 AB/BL=AC/CL x/4=2x/2x-4 X(2x-4)=4.2x 2x-12x=0/:2 X-6x=0 X(x-6)=0 x=0,x=6 AB=6 AC=AB=12 P тр.=12+12+6=30см.

  8. Задача 5 : тр.ABC,P тр.=20,CL=l ъгъл c (L e AB),AL=3 ,BL=5 AB=AL+LB AB=3+5=8 AC+BC=20-8=12 AC=x BC=12-x x/3=12-x/5 5x=3(12-x) 5x=36-3x 8x=36 X=4,5 AC=4,5 BC=12-4,5=7,5

  9. Задача 6 : Тр.АBC CD=l ъгъл c(D=AB) AC=+3 P=? CA/AB=CB/BD 2/x=x+3/2 2.2=x(x+3) 4=x2+3x X2+3x-4=0 A=1 b=3 c=-4 D=9+16=25=25=5 X12=-3+-5=1,-4 OTG.1x e решение

More Related