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Use of Bond Equations in Solving Problems

Use of Bond Equations in Solving Problems. Ray A. Gross Jr Prince George’s Community College. How many bonds are present in benzene, C 6 H 6 ?. Consider Water, H 2 O. For C 6 H 6. B = ½[(6 x 4) + (6 x 1)] B = ½(24 + 6) B = 15. Alternative Solution Hydrocarbons.

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Use of Bond Equations in Solving Problems

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  1. Use of Bond Equations in Solving Problems Ray A. Gross Jr Prince George’s Community College

  2. How many bonds are present in benzene, C6H6?

  3. Consider Water, H2O

  4. For C6H6 • B = ½[(6 x 4) + (6 x 1)] • B = ½(24 + 6) • B = 15

  5. Alternative Solution Hydrocarbons • Total Bonds = Bonds (corresponding saturated, acyclic compound) minus number of p bonds and rings in the structure.

  6. BD for Hydrocarbons

  7. BD for All Compounds BD = 1 – ½(X – N – 2C – 3P – 4S) X = number of monovalent atoms N = number of trivalent atoms C = number of tetravalent atoms P = number of pentavalent atoms S = number of hexavalent atoms

  8. Taxol, C47H51NO14 , has 7 rings.How many s bonds does it have? • + r = 1 – ½(X – N – 2C – 3P – 4S) p + r = 1 – ½[(51 – 1 – 2(47)] = 23 p = 23 – 7 = 16 B = ½[47(4) + 51 + 3 + 14(2)] = 135 s = 135 – 16 = 119

  9. How many bonds are in HPO4-2? B = ½[1 + 5 + 4(2) – 2] = 6

  10. What’s all of this good for? • Increases students knowledge of structure and bonding. • Possibly use DB to classify reactions.

  11. Derive an Eqn for Btot in an Alkyne. B = Bsat – BD B = 3n + 1 – 2 B = 3n - 1

  12. Dehydration of Cyclohexanol

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