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FINAL EXAM. MISCELLANEOUS REVIEW. PERIMETER, AREA, SURFACE AREA, AND VOLUME. QUESTION #1. FIND THE PERIMETER FIGURE BELOW. ANSWER #1. FIND THE PERIMETER FIGURE BELOW. P = 8 x + 12. QUESTION #2. FIND THE PERIMETER FIGURE BELOW. ANSWER #2. FIND THE PERIMETER FIGURE BELOW. P = 11x + 4.
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FINAL EXAM MISCELLANEOUS REVIEW
QUESTION #1 • FIND THE PERIMETER FIGURE BELOW.
ANSWER #1 • FIND THE PERIMETER FIGURE BELOW. P = 8x + 12
QUESTION #2 • FIND THE PERIMETER FIGURE BELOW.
ANSWER #2 • FIND THE PERIMETER FIGURE BELOW. P = 11x + 4
QUESTION #3 • FIND THE AREA OF THE FIGURE BELOW.
ANSWER #3 • FIND THE AREA OF THE FIGURE BELOW. A = 1.1 in2
QUESTION #4 • FIND THE AREA OF THE ORANGE SECTION IN THE FIGURE BELOW.
QUESTION #4 • FIND THE AREA OF THE ORANGE SECTION IN THE FIGURE BELOW. A = 201.0 in2
QUESTION #5 • THE LENGTH OF A RECTANGLE IS 3 MORE THAN THE WIDTH. IF THE DIMENSIONS OF THIS RECTANGLE ARE INCREASED BY 300%. • WHAT IS THE AREA OF THE ORIGINAL FIGURE? • WHAT IS THE NEW TOTAL AREA? • WHAT IS THE AREA OF THE EXPANDED REGION?
ANSWER #5 • THE LENGTH OF A RECTANGLE IS 3 MORE THAN THE WIDTH. IF THE DIMENSIONS OF THIS RECTANGLE ARE INCREASED BY 300%. • WHAT IS THE AREA OF THE ORIGINAL FIGURE? • WHAT IS THE NEW TOTAL AREA? • WHAT IS THE AREA OF THE EXPANDED REGION? A = x2 + 3x A = 9x2+ 27x A = 8x2+ 24x
QUESTION #6 • FIND THE VOLUME OF A RECTANGULAR PRISM IF THE LENGTH OF THE BASE IS (3X+2), THE WIDTH OF THE BASE IS (X-1), AND THE HEIGHT OF THE PRISM IS (X+4).
ANSWER #6 • FIND THE VOLUME OF A RECTANGULAR PRISM IF THE LENGTH OF THE BASE IS (3X+2), THE WIDTH OF THE BASE IS (X-1), AND THE HEIGHT OF THE PRISM IS (X+4). V = 3x3 + 11x2 – 6x - 8
QUESTION #7 • USE THE SOLID FROM THE PREVIOUS PROBLEM AND DOUBLE THE DIMENSIONS! FIND THE VOLUME.
QUESTION #7 • USE THE SOLID FROM THE PREVIOUS PROBLEM AND DOUBLE THE DIMENSIONS! FIND THE VOLUME. V = (6x+4)(2x-2)(2x+8) V = 24x3+88x2-48x-64 (Volume triples when dimensions double)
QUESTION #8 • FIND THE PROBABILITY OF EACH OUTCOME. • P(LESS THAN 3) A DIE IS ROLLED.
ANSWER #8 • FIND THE PROBABILITY OF EACH OUTCOME. • P(LESS THAN 3) = 2/6 = 1/3 A DIE IS ROLLED.
QUESTION #9 • FIND THE PROBABILITY OF EACH OUTCOME. • P(INTEGER) A DIE IS ROLLED.
ANSWER #9 • FIND THE PROBABILITY OF EACH OUTCOME. • P(INTEGER) = 6/6 = 1 A DIE IS ROLLED.
QUESTION #10 • A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. • P(NOT DIME) A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS.
ANSWER #10 • A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. • P(NOT DIME) = 110/140 A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS.
QUESTION #11 • A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. • P(NICKEL OR QUARTER) A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS.
QUESTION #11 • A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. • P(NICKEL OR QUARTER) • 27/140 + 18/140 = 40/140 = 2/7 A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS.
QUESTION #12 • FIND EACH PROBABILITY. • P(LESS THAN 14) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
ANSWER #12 • FIND EACH PROBABILITY. • P(LESS THAN 14) = 13/28 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
QUESTION #13 • FIND EACH PROBABILITY. • P(NOT 2 OR 17) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
ANSWER #13 • FIND EACH PROBABILITY. • P(NOT 2 OR 17) • = 1/28 + 1/28 = 2/28 = 1/14 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
QUESTION #14 • FIND EACH PROBABILITY. • P(13) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
QUESTION #14 • FIND EACH PROBABILITY. • P(13) = 1/28 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS.
QUESTION #15 • WHAT IS THE PROBABILITY THAT THE SPINNER WITH LAND ON WHITE SECTION AND DIE WILL LAND ON 6? BRENDAN SPINS A SPINNER EQUALLY COLORED IN RED, BLUE, GREEN, AND WHITE AND ROLLS A FAIR DIE.
QUESTION #15 • WHAT IS THE PROBABILITY THAT THE SPINNER WITH LAND ON WHITE SECTION AND DIE WILL LAND ON 6? • P(W, 6) = 1/4*1/6=1/24 BRENDAN SPINS A SPINNER EQUALLY COLORED IN RED, BLUE, GREEN, AND WHITE AND ROLLS A FAIR DIE.
QUESTION #16 • FIND THE PROBABILITY OF PICKING A BLACK THEN ANOTHER BLACK, WITHOUT REPLACEMENT. IN A BAG, THERE ARE 3 BLUE, 2 GREEN, AND 5 BLACK MARBLES.
ANSWER #16 • FIND THE PROBABILITY OF PICKING A BLACK THEN ANOTHER BLACK, WITHOUT REPLACEMENT. • P(B, B)=5/10*4/9=2/9 IN A BAG, THERE ARE 3 BLUE, 2 GREEN, AND 5 BLACK MARBLES.
QUESTION #17 • HOW MANY DIFFERENT OUTFITS CAN SHE MAKE? ANNALISE WENT SHOPPING AND BOUGHT 4 T-SHIRTS, 3 SKIRTS, AND 2 SHOES.
QUESTION #17 • HOW MANY DIFFERENT OUTFITS CAN SHE MAKE? • 4*3*2=24 ANNALISE WENT SHOPPING AND BOUGHT 4 T-SHIRTS, 3 SKIRTS, AND 2 SHOES.
QUESTION #18 THE VENN DIAGRAM BELOW SHOWS THE TYPES OF NOVELS THE LITERATURE CLUB MEMBERS READ DURING THEIR SUMMER BREAK. • IF 133 STUDENTS ARE IN THE LITERATURE CLUB MEMBERS AND ALL STUDENTS READ AT LEAST ONE BOOK, HOW MANY STUDENTS READ ADVENTURE AND MYSTERY?
QUESTION #18 THE VENN DIAGRAM BELOW SHOWS THE TYPES OF NOVELS THE LITERATURE CLUB MEMBERS READ DURING THEIR SUMMER BREAK. • IF 133 STUDENTS ARE IN THE LITERATURE CLUB MEMBERS AND ALL STUDENTS READ AT LEAST ONE BOOK, HOW MANY STUDENTS READ ADVENTURE AND MYSTERY? • 133-(36+14+7+43+3+28)=2
QUESTION #19 • FIND THE MISSING LENGTH.
ANSWER #19 • FIND THE MISSING LENGTH. b = 112.5 units
QUESTION #20 • FIND THE MISSING LENGTH.
QUESTION #20 • FIND THE MISSING LENGTH. b = 7.2 units
QUESTION #21 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.
QUESTION #21 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. 92+402=412 is true, so it is a right triangle
QUESTION #22 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.
ANSWER #22 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. 42+√262=122 is NOT true, so it is NOT a right triangle
QUESTION #23 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.
QUESTION #23 • DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. (√65)2+(6√2)2=(√97)2 is NOT true, so it is NOT a right triangle