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Gas Laws

Gas Laws. B. Charles’s Law - the temperature of a gas is directly proportional to the volume (provided the pressure remains constant) The temperature must be in Kelvins! Mathematical equation: V 1 = V 2 T 1 T 2

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Gas Laws

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  1. Gas Laws B. Charles’s Law- the temperature of a gas is directly proportional to the volume (provided the pressure remains constant) • The temperature must be in Kelvins! • Mathematical equation: V1 = V2 T1 T2 • One value will increase as the other increases, or decrease as the other decreases

  2. Gas Laws • Charles’s Law: Sample Problem What would be the resulting volume of a 2.0 L balloon at 25.0°C that was placed in a container of ice water at 3.0°C? Hint: First identify the values of the symbols in the Charles’s Law equation. Then, convert the temperature values to Kelvins!

  3. Gas Laws What would be the resulting volume of a 2.0 L balloon at 25.0°C that was placed in a container of ice water at 3.0°C? Hint: First identify the values of the symbols in the Charles’s Law equation. Then, convert the temperature values to Kelvins! T1 = 25.0°C V1 = 2.0 L V1 = V2 T2 = 3.0°C T1 T2 V = ???

  4. Gas Laws What would be the resulting volume of a 2.0 L balloon at 25.0°C that was placed in a container of ice water at 3.0°C? Hint: First identify the values of the symbols in the Charles’s Law equation. Then, convert the temperature values to Kelvins! T1 = 298 K V1 = 2.0 L 2.0 L = V2__ T2 = 276 K 298 K 276 K V = ???

  5. Gas Laws C. Gay-Lussac’s Law- the temperature of a gas is directly proportional to the pressure (provided the volume and mass remains constant) • The temperature must be in Kelvins! • Mathematical equation: P1 = P2 T1 T2 • One value will increase as the other increases, or decrease as the other decreases

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