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Probability and Pedigree Practice Problems. Pick a card. Today. Practice probability problems Practice will help in doing these types of questions. Any problems you do not have time to do, try doing later. Practice. 1. Work on the probability problems on pages 1-4 and 1-5 of the lab manual
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Probability and Pedigree Practice Problems Pick a card
Today • Practice probability problems • Practice will help in doing these types of questions. • Any problems you do not have time to do, try doing later.
Practice • 1. Work on the probability problems on pages 1-4 and 1-5 of the lab manual • 2. Pedigrees and probability problems 1-28 and 1-30. These you may need to complete at home. • Please refer to Dr. Colavito’s homepage for solutions.
Begin with page 1-4 • 1. • A) Probability of rolling a “5”= 1/6 • B) Probability of rolling an even number: 1/6 + 1/6 + 1/6 = 1/2
Problem 1 continued • 1c) 1/6 x 1/6 x1/6 = 1/216 • 1d) 6x(1/216)=1/36 • 1e) 1/216 x 6 = 1/36 • 1f) 1 (any number) x 5/6 x 4/6 = 20/36= 5/9
Problem 2 • First identify the probabilities of selecting various colors: • Jar 1: P (y)= 1/5 P (G) = 4/5 • Jar 2 :P (O) = 2/5 P(G) 3/5 • Jar 3 :P (P) 1/10 P(G) 9/10
Problem 2 • A. 1/5 x 2/5 x 1/10 = 2/250 = 1/125 • B. 4/5 x 2/5 x 9/10 = 72/250 • C. 1-(probability of no green skittles, see part A.)= 1-1/125=124/125
Problem 2 • D. calculate all possible combinations for each container: • (4/5 x 3/5 x 1/10) + (4/5 x 2/5 x 9/10) + 1/5 x 3/5 x 9/10) = 111/250
Problem 2 • E. (2/5 x 1/10 x 4/5) = 8/250= 4/125
Problem 3 Autosomal Dominant • A. ¾ • B. 4!/3!1! (1/4)3 (3/4)1= 3/64 • C. ¼ x ¾ x/ ¾ = 9/64 • D. 1-(probability that all will have straight little fingers)= 1-(1/4) 3= 63/64
Problem 4: Autosomal Recessive • A. 2/3 • B. 2/3 • Keep in mind the parents of Jessica and Jerry must be heterozygous for in order to have a sibling that has CF.
Problem 4 • C. 2/3 x 2/3 x 1/4 = 1/9 • Remember to refer to your Punnett square and you will see that with heterozygous parents there is ¼ chance of cc.
Problem 4 • D. 3!/2!1! (1/9)2 (8/9)1 = 8/243 • E. 8/9 x 1/9 x 8/9 = 64/729
Problem 5: X linked recessive • ½ that Polly has the “d” allele • ½ x ¼ =1/8 • ½ x 3/8 x 1/8 = 3/128 • 5!/2!3! (1/8)2 (7/8) 3 = 3430/32768 =0.105
Pedigrees (page 1-26) • A. autosomal dominant • B. X linked dominant • C. X linked recessive • D. autosomal recessive • E. X-linked dominant • F. Autosomal recessive • G. Autosomal Dominant • H. X-linked recessive
Answers • Check Dr. Colavito’s homepage “study guide” to check your answers.