110 likes | 265 Views
Light. e –. A. I. V 0. I 0. V. 0. f 0. f. 0. Photoelectric Effect. - V 0. 1) Current depends on potential; max current I 0 (saturation) for high voltages. I 0 reached when all electrons are collected
E N D
Light e– A I V0 I0 V 0 f 0 f 0 Photoelectric Effect -V0 1) Current depends on potential; max current I0 (saturation) for high voltages. I0 reached when all electrons are collected 2) Positive current even for (small) negative potential up to V0 (“stopping potential”). V0 corresponds to max. Ekin: eV0 = Ekin, max 3) I0 (= # of electrons per time) depends on light intensity but NOT on frequency 4) V0 depends on the material and frequency, but not on intensity. 5) Emission only occurs for frequencies f > f 0(V0(f 0) = 0 ) 6) The current is always observed immediately with begin of irradiation. Interpretation: Light comes in bundles (photons) with energy E = hf, each photon is absorbed by a single electron. # of electrons # of incident photons e– emitted only if photon energy is larger than e– separation energy (“work function”): hf> w0 Kinetic energy of electron: Ekin, max= h f– w0 stopping potential: eV0 = Ekin, max= h f– w0 ; threshold frequency (Ekin = 0) : f 0= w0/h
Vacuum tube Cathode Anode – + Wilhelm Röntgen – X-rays Roentgen’s original tube cathode rays Very first “medical” x-ray exposure: Berta Roentgen’s hand, December 22, 1895 http://www.deutsches-museum.de/sammlungen/ausgewaehlte-objekte/meisterwerke-ii/roentgen/
Wave front d q d sin q Crystal lattice Bragg reflection of x-rays Bragg condition: 2d sin q = nl Crystal x-ray www.unl.edu/ncmn/facilities/images/Lauebkg_sm.gif
Bragg reflection of x-rays Polycrystalline powder Single crystal
Compton Scattering Conservation of energy Ei + mec2 = Ef + Ee Conservation of momentum x: pi = pfcosq + pecosj y: 0 = pf sin q + pe sin j Ee2 = pe2c2 + me2c4; Ei,f = pi,f c Ee, pe Ei, pi j q Ef, pf Change in wavelength: Dl = lC (1-cosq) with lC = h/mec = 2.43×10-12 m
Temperature [K] Energy [eV] ultra- violet micro- wave x-rays γ-rays infrared radio Frequency [Hz] 1010 10-16 1014 1024 10-14 108 1022 1012 1020 10-12 106 1010 1018 108 104 10-10 1016 106 102 10-8 1014 100 10-6 104 10-2 102 10-4 1012 1010 10-2 10-4 100 108 100 10-6 10-2 10-8 10-4 102 106 10-10 104 104 10-6 Wavelength [m] Visible Wavelength [nm] 400 450 500 550 600 650 700 750 Electromagnetic Spectrum
Light emission Spectra Source: http://library.tedankara.k12.tr Thermal radiation – continuous spectrum Radiation of gases (e.g. H) – discrete spectrum Source: http://mo-www.harvard.edu/Java/MiniSpectroscopy.html
X-ray emission Bremsstrahlung + characteristic emission Source: http://www.uni-koeln.de/math-nat-fak/geomin/images/ausstattung/xerzeug.gif
Cross section and Interaction Probability Target, rt Projectile, rp Cross section: p(rp+rt)² Number of interactions N: N = nsfDt n: number of targets per area s: (total) cross section [ ns: fraction of total area covered with “disks”] f: flux of projectiles (# of projectiles/time) [ fDt: total number of projectiles] Interaction probability per projectile P: P = ns
Cross section and Interaction Probability Photo effect Cross section for the interaction of photons with C atoms (1 barn = 10-28 m²) http://xdb.lbl.gov/Section3/Sec_3-1.html 41 Pair production (momentum transfer to nucleus) Thomson scattering Pair production (momentum transfer to electron) Compton scattering
Matter and Radiation Energy from matter to radiation: emission - Continuous: thermal radiation, bremsstrahlung - Discrete: atomic spectra, characteristic x-rays - Radioactive decay (gamma radiation, but also other radiation) Energy from radiation to matter: absorption, scattering - Photoelectric effect - Compton scattering - Pair production Cross section(s) Probability for interaction (Number of interactions N = nsfDt, n: targets per area, f : flux of projectiles) Attenuation Beam of photons propagating through material Intensity at position x: I(x) Intensity at x+dx: I(x) – probability that something happens in dx I(x+dx) = I(x) – I(x)sn = I(x) – I(x)srdx (r : atoms per volume) dI/dx = (I(x+dx) – I(x))/dx = – srI(x) I(x) = I0 exp( – sr x)