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Gamma and X ray interactions. NUCP 2371 Rad Pro III. EM Energy. Energy of the EM radiation is determined by its frequency E= hf h= planks constant =6.6 x 10 -34 J sec Or 4.1 x 10 -15 eV sec F= frequency of the EM radiation Frequency is the inverse of wavelength. Photon Interactions.
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Gamma and X ray interactions NUCP 2371 Rad Pro III
EM Energy • Energy of the EM radiation is determined by its frequency • E= hf • h= planks constant =6.6 x 10 -34 J sec • Or 4.1 x 10 -15 eV sec • F= frequency of the EM radiation • Frequency is the inverse of wavelength
Photon Interactions • Rayleigh Scattering • Thompson scattering • Photoelectric Effect • Compton Scattering • Pair production • Nuclear transformations
Rayleigh Scattering • Is the scattering of light or other low energy electromagnetic radiation by particles much smaller than the wavelength of the light, such as an atom or molecule • The amount of scattering that occurs is dependent upon the size of the particles and the wavelength of the light. • Usually the EM ray bounces off the electron with no change in energy • the main reason why the sky is blue
Rayleigh scattering greater proportion of blue light scattered by the atmosphere relative to red light. (from Wikipedia)
Thompson Scattering • Free charged particle absorbs the gamma ray • The particle oscillates in an excited state • Then radiates the gamma ray in a random direction • The energy is the same but is going in a different direction • Background microwave radiation
Photoelectric Effect • Low energy gamma or x ray interactions • Electron absorbs all of the energy of the incoming EM wave and has enough energy to break away from the atom to which it is associated • First observed by Hertz in 1887 • N Tesla received a patent for a photoelectric motor in 1901 • Explained by Einstein in 1905
Photoelectric Effect Ejected Electron Incoming Photon Photoelectric Effect: Predominates with incident photons of low energy; complete energy transfer of the incoming photon to the ejected electron
Photoelectric Equation Ee- = E - B.E. Ee- = kinetic energy of the ejected electron E = energy of the X-ray or gamma ray B.E. = binding energy of the orbital electron Probability if PE effect occurring is proportional to the Z of the material and inversely proportional to the energy of the EM wave
Compton Scattering • Medium energy EM wave interaction in which the electron absorbs some of the energy of the EM wave and get ejected from the atom , but he secondary EM is created with a wavelength greater (less energy)than that of the incoming EM wave • Discovered by A Compton in 1923
Compton Scattering Scattered Photon Incoming Photon Ejected Electron Compton Scattering: Predominates with incident photons of medium energy; partial energy transfer of the incoming photon to the ejected electron and the scattered photon.
Compton Equation • Δλ = λc(1 - cos θ), • Δλ = the difference in wavelength of incomeing and scattered EM wave λc is the Compton wavelength of the electron (h/mc= 2.43 X 10-12 m) θ is the angle between the directions of incident and scattered radiation.
Difference in wavelength • What is the new energy of a compton scattered ER ray if the ER is scattereded through an angle of 400
SHIELDING • Backscatter Deflection of radiation by scattering process through angles greater than 90 degrees with respect to the original direction of motion What does this mean? What are the implications?
Pair Production • High energy EM interaction, EM wave comes in very close to the nucleus and spontaneously disappears and two charged particles(Beta – and +) are created • First observed by Patrick Blackett
Pair Production Emitted Annihilation Photons + Incident Photon - Detector Material Pair Production: Predominates with incident photons of high energy (at least 1.02 MeV); Positron and electron formed, then two 0.51 MeV annihilation photons are emitted
Pair production • Can occur when the gamma energy is above 1.022 MeV but does not occur in any appreciable percentage until the gamma energy is >5MeV • Electron will get captured • Positron will find an electron and will annialate producing two 511 keV gamma rays
Nuclear transformation • Occurring at high energies >6 MeV • EM ray gets absorbed by the nucleus • A particle, usually a neutron, is emitted from the nucleus