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Chapter 18: Electrical Properties

Chapter 18: Electrical Properties. ISSUES TO ADDRESS. • How are electrical conductance and resistance characterized ?. • What are the physical phenomena that distinguish conductors, semiconductors, and insulators?. • For metals, how is conductivity affected by

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Chapter 18: Electrical Properties

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  1. Chapter 18: Electrical Properties ISSUES TO ADDRESS... • How are electrical conductance and resistance characterized? • What are the physical phenomena that distinguish conductors, semiconductors, and insulators? • For metals, how is conductivity affected by imperfections, temperature, and deformation? • For semiconductors, how is conductivity affected by impurities (doping) and temperature?

  2. Ohm’s Law

  3. Electrical Conduction • Resistivity, r: -- a material property that is independent of sample size and geometry surface area of current flow current flow path length • Conductivity, s • Ohm's Law: V = I R voltage drop (volts = J/C) C = Coulomb resistance (Ohms) current (amps = C/s)

  4. Electrical Properties • Which will have the greater resistance? • Analogous to flow of water in a pipe • Resistance depends on sample geometry and size. 2 D 2D

  5. J =  (V/ ) Electron fluxconductivityvoltage gradient Definitions Further definitions J=   <= another way to state Ohm’s law J  current density   electric field potential = V/

  6. Conductivity: Comparison CERAMICS Soda-lime glass 10 -9 Concrete 10 -13 Aluminum oxide <10 SEMICONDUCTORS POLYMERS -14 -4 Polystyrene <10 Silicon 4 x 10 -15 -10 -17 -11 0 Polyethylene 10 -10 -10 Germanium 2 x 10 -6 GaAs 10 insulators semiconductors • Room temperature values (Ohm-m)-1 = ( - m)-1 METALS conductors 7 Silver 6.8 x 10 7 Copper 6.0 x 10 7 Iron 1.0 x 10 Selected values from Tables 18.1, 18.3, and 18.4, Callister & Rethwisch 8e.

  7. Example: Conductivity Problem What is the minimum diameter (D) of the wire so that V < 1.5 V? I = 2.5 A + - Cu wire V 100 m < 1.5 V 2.5 A 6.07 x 107 (Ohm-m)-1 Solve to get D > 1.87 mm

  8. 18.2An aluminum wire 10 m long must experience a voltage drop of less than 1.0 V when a current of 5 A passes through it. Using the data in Table 18.1, compute the minimum diameter of the wire.

  9. Electron Energy Band Structures Adapted from Fig. 18.2, Callister & Rethwisch 8e.

  10. Band Structure Representation Adapted from Fig. 18.3, Callister & Rethwisch 8e.

  11. Partially filled band Overlapping bands Energy Energy empty band empty GAP band partly filled filled band band filled states filled states filled filled band band Conduction & Electron Transport • Metals (Conductors): -- for metals empty energy states are adjacent to filled states. -- thermal energy excites electrons into empty higher energy states. -- two types of band structures for metals - partially filled band - empty band that overlaps filled band

  12. Energy Band Structures: Insulators & Semiconductors • Semiconductors: -- narrow band gap (< 2 eV) -- more electrons excited across band gap empty empty Energy conduction conduction band band ? GAP filled valence band filled states filled band • Insulators: -- wide band gap (> 2 eV) -- few electrons excited across band gap Energy GAP filled valence band filled states filled band

  13. Electron Mobility

  14. 6 r • Resistivity increases with: Cu + 3.32 at%Ni 5 Ohm-m) 4 -- temperature deformed Cu + 1.12 at%Ni Resistivity, -- wt% impurity 3 Cu + 1.12 at%Ni d -8 -- %CW 2 (10 i  = thermal “Pure” Cu 1 t + impurity 0 -200 -100 0 T (ºC) + deformation Adapted from Fig. 18.8, Callister & Rethwisch 8e. (Fig. 18.8 adapted from J.O. Linde, Ann. Physik5, p. 219 (1932); and C.A. Wert and R.M. Thomson, Physics of Solids, 2nd ed., McGraw-Hill Book Company, New York, 1970.) Metals: Influence of Temperature and Impurities on Resistivity • Presence of imperfections increases resistivity -- grain boundaries -- dislocations -- impurity atoms -- vacancies These act to scatter electrons so that they take a less direct path.

  15. Adapted from Fig. 18.9, Callister & Rethwisch 8e. 180 50 r 160 Ohm-m) 40 140 125 30 30 Resistivity, 120 Yield strength (MPa) -8 20 100 (10 21 wt% Ni 10 80 0 60 0 10 20 30 40 50 0 10 20 30 40 50 wt% Ni, (Concentration C) wt% Ni, (Concentration C) From step 1: CNi = 21 wt% Ni Estimating Conductivity • Question: -- Estimate the electrical conductivity  of a Cu-Ni alloy that has a yield strength of 125 MPa. Adapted from Fig. 7.16(b), Callister & Rethwisch 8e.

  16. Charge Carriers in Insulators and Semiconductors Two types of electronic charge carriers: Free Electron – negative charge – in conduction band Hole – positive charge – vacant electron state in the valence band Adapted from Fig. 18.6(b), Callister & Rethwisch 8e. Move at different speeds - drift velocities

  17. Intrinsic Semiconductors • Pure material semiconductors: e.g., silicon & germanium • Group IVA materials • Compound semiconductors • III-V compounds • Ex: GaAs & InSb • II-VI compounds • Ex: CdS & ZnTe • The wider the electronegativity difference between the elements the wider the energy gap.

  18. • Electrical Conductivity given by: # holes/m3 hole mobility electron mobility # electrons/m3 Intrinsic Semiconduction in Terms of Electron and Hole Migration

  19. Room Temperature Values

  20. for intrinsic semiconductor n = p = ni  = ni|e|(e+ h)  • Ex: GaAs For GaAs ni = 4.8 x 1024 m-3 For Si ni = 1.3 x 1016 m-3 Number of Charge Carriers Intrinsic Conductivity

  21. Intrinsic Semiconductors: Conductivity vs T • Data for Pure Silicon: -- s increases with T -- opposite to metals material Si Ge GaP CdS band gap (eV) 1.11 0.67 2.25 2.40 Selected values from Table 18.3, Callister & Rethwisch 8e. Adapted from Fig. 18.16, Callister & Rethwisch 8e.

  22. 18.21 At room temperature the electrical conductivity of PbTe is 500 (Ω-m)–1, whereas the electron and hole mobilities are 0.16 and 0.075 m2/V-s, respectively. Compute the intrinsic carrier concentration for PbTe at room temperature.

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