1 / 10

Equilibrant Force for Creating Equilibrium in Hanging Sign Problems

Learn to calculate tension in ropes supporting a motionless sign by analyzing forces in equilibrium, using trigonometry & problem-solving techniques.

ehannon
Download Presentation

Equilibrant Force for Creating Equilibrium in Hanging Sign Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Forces & Equilibrium

  2. Equilibrant Forces • Equilibrant– A single, additional force that is exerted on an object to produce equilibrium, which is the same magnitude as the resultant force but opposite in direction

  3. Creating EquilibriumHanging Sign • A 168-N sign is supported in a motionless position by two ropes that each make 22.5 angles with the horizontal. What is the tension in the rope? Θ Θ sign

  4. Creating Equilibrium • Given •  = 22.5 • Fg = 168-N Unknown FA = ? FB = ? FA FB Fg

  5. Creating Equilibrium • Given •  = 22.5 • Fg = 168-N Unknown FA = ? FB = ? FA FB Θ Θ Fg

  6. Creating Equilibrium • Notice that each tension force (FT) can be broken down into its x and y components.

  7. Creating Equilibrium • Each string holds half of the weight b/c the angles are the same • Therefore the y component for each string is half of Fg(168N / 2 = 84N) • Simple trig  sinΘ = Opp/Hyp • Solve for Hyp (aka FT)

  8. Creating Equilibrium • Given •  = 22.5 • Fg = 168-N Unknown FA = ? FB = ? FA FB 84N 84N Θ Θ Fg

  9. Creating Equilibrium • sin 22.5° = 84N / Hyp • Hyp = 84N /(sin 22.5) • FT = Hyp = 220N

  10. Hanging Sign Practice Problem • A 150-N sign is suspended by two wires that make an angle of 130with each other. The tension in the wires are equal. • Draw a pictorial diagram • Draw a free-body diagram • What is the tension in the wires

More Related