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AP Physics Chapter 4 Force and Motion

AP Physics Chapter 4 Force and Motion. Chapter 4: Force and Motion. 4.1 The Concepts of Force and Net Force 4.2 Inertia and Newton’s First Law of Motion 4.3 Newton’s Second Law of Motion 4.4 Newton’s Third Law of Motion 4.5 Free-body Diagrams and Translational Equilibrium

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AP Physics Chapter 4 Force and Motion

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  1. AP Physics Chapter 4Force and Motion

  2. Chapter 4: Force and Motion 4.1 The Concepts of Force and Net Force 4.2 Inertia and Newton’s First Law of Motion 4.3 Newton’s Second Law of Motion 4.4 Newton’s Third Law of Motion 4.5 Free-body Diagrams and Translational Equilibrium 4.6 Friction

  3. Homework for Chapter 4 • Read Chapter 4.1-4.3 • HW 4.1-4.3 pg 130-132 #1-36 • Omit 5,6,13,32,33

  4. 4.1 The Concepts of Force and Net Force dynamics – what causes motion and changes in motion. • Isaac Newton summarized the “why” of motion with three laws. force – something capable of changing an object’s state of motion (its velocity) • a vector quantity • SI unit is the newton • A newton of force causes a 1 kg mass to accelerate 1 m/s2. • 1 N = 1kg · m s2 net force – the vector sum, or resultant, of all the forces acting on an object. • can be written as ∑ F • balanced forces create zero net force • unbalanced forces create a net force • a net force produces an acceleration

  5. 4.1 The Concepts of Force and Net Force

  6. 4.1 The Concepts of Force and Net Force

  7. 4.2 Inertia and Newton’s First Law of Motion

  8. 4.2 Inertia and Newton’s First Law of Motion

  9. 4.2 Inertia and Newton’s First Law of Motion inertia – the natural tendency of an object to maintain a state of rest or to remain in uniform motion in a straight line (constant velocity). inertial frame of reference – a non-accelerating frame of reference. - a frame of reference where Newton’s 1st Law holds. ex: juggling on a bus travelling at constant velocity. non-inertial frame of reference – an accelerating frame of reference where fictitious forces arise. ex: having to hang on to a merry-go-round, or be thrown off! mass – a measure of inertia ** If the net force acting on an object is zero, then its acceleration is zero.***

  10. 4.2 Inertia and Newton’s First Law of Motion

  11. 4.2 Inertia and Newton’s First Law of Motion

  12. 4.3 Newton’s Second Law of Motion

  13. 4.3 Newton’s Second Law of Motion

  14. 4.3 Newton’s Second Law of Motion

  15. 4.3 Newton’s Second Law of Motion

  16. 4.3 Newton’s Second Law of Motion

  17. 4.3 Newton’s Second Law of Motion

  18. 4.3 Newton’s Second Law of Motion

  19. 4.3 Newton’s Second Law of Motion

  20. 4.3 Newton’s Second Law of Motion

  21. 4.3 Newton’s Second Law of Motion

  22. 4.3 Newton’s Second Law of Motion

  23. 4.3 Newton’s Second Law of Motion

  24. 4.3 Newton’s Second Law of Motion

  25. 4.3 Newton’s Second Law of Motion

  26. 4.4 Newton’s Third Law of Motion

  27. 4.4 Newton’s Third Law of Motion

  28. 4.4 Newton’s Third Law of Motion

  29. 4.4 Newton’s Third Law of Motion

  30. 4.4 Newton’s Third Law of Motion

  31. 4.4 Newton’s Third Law of Motion

  32. Check for Understanding • Fill in the blanks using the word bank. • velocity mass dynamics weight “the same” • acceleration non-inertial kinematics inertial different • _________________is used to analyze motion, but ________________ explains what causes motion and changes in motion. • A(n)_____________ frame of reference is non-accelerating. • In a(n) ________________ frame of reference, fictitious forces arise. • The gravitational force on an object near Earth’s surface is called ________. • With no forces acting upon it, an object moves with constant ____________. • In an action/reaction pair, both forces must act on __________ object(s).

  33. Check for Understanding • Fill in the blanks using the word bank. • velocity mass dynamics weight “the same” • acceleration non-inertial kinematics inertial different • Kinematics is used to analyze motion, but dynamics explains what causes motion and changes in motion. • A(n) inertial frame of reference is non-accelerating. • In a(n) non-inertial frame of reference, fictitious forces arise. • The gravitational force on an object near Earth’s surface is called weight. • With no forces acting upon it, an object moves with constant velocity. • In an action/reaction pair, both forces must act on different object(s).

  34. Homework 4ACovers Sections 4.1-4.4: Newton’s Laws • HW 4A: pp. 131-132: 13, 22, 34, 35, 43, 44.

  35. Lesson 4.5: Free Body Diagrams and Translational Equilibrium

  36. Fground on car Fforward Fresistance Fgravity

  37. 4.5 Free-body Diagrams and Translational Equilibrium Problems we will solve will generally have constant forces and therefore have constant accelerations. This allows us to use the kinematics equations and Newton’s Laws to analyze motion. Free-body Diagrams 1. Sketch the problem. Draw all force vectors. 2. Pick the body to be analyzed using a free-body diagram. Draw a dot at the center of this body. Draw the origin of your x-y axes at this point. Draw one of the axes along the direction of the body’s acceleration. 3. Draw and label all force vectors acting on the body with their tails on the dot. If the body is accelerating, draw an acceleration vector. 4. Resolve any forces not directed along an x or y axis into their components. 5. Use Newton’s second law to write equations for the x and y directions. Solve!

  38. 4.5 Free-body Diagrams and Translational Equilibrium

  39. Solution: Isolate the body which we wish to analyze and draw a free-body diagram. T = tension holding up scale a = 20 m/s2 (this is what the scale will read) F.B.D. of spring scale weight = mg Fnet = T – mg and, Fnet = ma So, ma = T – mg Solve for T: T = ma + mg = m (a + g) = 100 kg (20 m/s2 + 10 m/s2) T = 3000 N, which is what the scale will read. The answer is d.

  40. Example 4.5:

  41. 4.5 Free-body Diagrams and Translational Equilibrium Pulley Problems • a string is considered massless for our purposes • the tension is the same everywhere in a string • a single, fixed pulley simply changes the direction of a force Atwood’s Machine • The acceleration of an object depends on the net applied and the object’s mass. • In an Atwood’s Machine, the difference in weight between two hanging masses determines the net force acting on both masses. • This net force accelerates both hanging masses; the heavier mass is accelerated downward, and the lighter mass is accelerated upward.

  42. Example 60: An Atwood machine has suspended masses of 0.25 kg and 0.20 kg. Under ideal conditions, what will be the acceleration of the smaller mass?

  43. 4.5 Free-body Diagrams and Translational Equilibrium Inclined Plane Problems Suppose we have a mass being accelerated by a rope up a frictionless inclined plane. 1. Make a sketch. Identify the forces acting on the mass. Here we have identified tension, weight, and the normal force. 2. Free-body diagram the mass. Draw a dot to represent the center of mass. Establish the x-axis along the plane, where positive is the direction of acceleration. The y-axis is perpendicular to the x-axis.

  44. 3. Draw force vectors in the proper directions pointing away from the dot. Draw an acceleration vector in the direction of the net force. 4. Resolve any forces that are not directed along the x or y axes into x or y components. Typically you will need to do this for the weight vector. Use the free-body diagram to analyze the forces in terms of Newton’s second law of motion.

  45. Example 4.6:

  46. Example 65: • In the ideal setup shown, m1 = 3.0 kg, m2 = 2.5 kg. • What is the acceleration of the masses? • What is the tension in the string?

  47. 4.5 Free-body Diagrams and Translational Equilibrium translational equilibrium – the object is at rest or constant velocity • the sum of the forces, Fnet = 0 • a = 0 static translational equilibrium – the object is at rest; v = 0 m/s. Hints for Static Equilibrium Problems • Remember, tension in a string is the same everywhere in the string. • Resolve force vectors into their components. • Sum x and y components separately. • Fnet = 0 for the x and y components

  48. 4.5 Free-body Diagrams and Translational Equilibrium

  49. 4.5 Free-body Diagrams and Translational Equilibrium

  50. Check for Understanding: Practice Problem A 2-kg block and a 5-kg block are shown. The surface is frictionless. Find the tension in the rope connecting the two blocks. 5 kg Solution: Draw free-body diagrams of both masses. 2 kg x+ FN T a a y+ M = 5 kg T m = 2 kg mg Mg Fnet x = T = Ma Fnet y = - T + mg = ma We have two equations and two unknowns, so we can solve it…

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