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11.19 Cyclobutadiene and Cyclooctatetraene. Heats of Hydrogenation. To give cyclohexane (kJ/mol):. Heat of hydrogenation of benzene is 152 kJ/mol, less than 3 times heat of hydrogenation of cyclohexene. 120. 231. 208. Heats of Hydrogenation. To give cyclooctane (kJ/mol):.
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Heats of Hydrogenation To give cyclohexane (kJ/mol): Heat of hydrogenation of benzene is 152 kJ/mol, less than 3 times heat of hydrogenation of cyclohexene. 120 231 208
Heats of Hydrogenation To give cyclooctane (kJ/mol): Heat of hydrogenation of cyclooctatetraene is more than 4 times heat of hydrogenation of cyclooctene. 97 205 303 410
Structure of Cyclooctatetraene Cyclooctatetraene is not planar; has alternating long (146 pm)and short (133 pm) bonds.
Structure of Cyclobutadiene MO calculations give alternating short and longbonds for cyclobutadiene. H H 135 pm 156 pm H H
C(CH3)3 (CH3)3C 138 pm 151 pm (CH3)3C CO2CH3 Structure of Cyclobutadiene Structure of a stabilized derivative is characterizedby alternating short bonds and long bonds.
Stability of Cyclobutadiene Cyclobutadiene is observed to be highly reactive, and too unstable to be isolated and stored in thecustomary way. Not only is cyclobutadiene not aromatic, it is antiaromatic. An antiaromatic substance is one that is destabilizedby cyclic conjugation.
notaromatic notaromatic aromatic Antiaromatic when square. Antiaromatic when planar. Requirements for Aromaticity Cyclic conjugation is necessary, but not sufficient.
Conclusion There must be some factor in additionto cyclic conjugation that determines whether or not a molecule is aromatic.
11.20Hückel's Rule: The additional factor that influences aromaticity is the number of electrons.
Hückel's Rule Among planar, monocyclic, completely conjugated polyenes, only those with 4n + 2 electrons possess special stability (are aromatic). n 4n+2 0 2 1 6 Benzene! 2 10 3 14 4 18
Hückel's Rule Hückel restricted his analysis to planar,completely conjugated, monocyclic polyenes. He found that the molecular orbitals ofthese compounds had a distinctive pattern. One orbital was lowest in energy, another was highest in energy, and the others were arranged in pairs between the highestand the lowest.
Hückel's Rule Frost's circle is a mnemonic that allows us to draw a diagram showing the relative energies ofthe p orbitals of a cyclic conjugated system. 1) Draw a circle. 2) Inscribe a regular polygon inside the circle so that one of its corners is at the bottom. 3) Every point where a corner of the polygon touches the circle corresponds to a p electron energy level. 4) The middle of the circle separates bonding and antibonding orbitals.
Antibonding Bonding p MOs of Benzene Frost's Circle
-MOs of Benzene Antibonding 6 p orbitals give 6 orbitals. 3 orbitals are bonding; 3 are antibonding. Benzene Bonding
-MOs of Benzene Antibonding 6 electrons fill all of the bonding orbitals. All antibonding orbitals are empty. Benzene Bonding
-MOs of Cyclobutadiene(Square Planar) Antibonding 4 p orbitals give 4 orbitals. 1 orbital is bonding, one is antibonding, and 2 are nonbonding. Cyclo-butadiene Bonding
-MOs of Cyclobutadiene(Square Planar) Antibonding 4 electrons; bonding orbital is filled; other 2 electrons singly occupy two nonbonding orbitals. Cyclo-butadiene Bonding
-MOs of Cyclooctatetraene(Planar) Antibonding 8 p orbitals give 8 orbitals. 3 orbitals are bonding, 3 are antibonding, and 2 are nonbonding. Cyclo-octatetraene Bonding
-MOs of Cyclooctatetraene(Planar) Antibonding 8 electrons; 3 bonding orbitals are filled; 2nonbonding orbitals are each half-filled. Cyclo-octatetraene Bonding
-Electron Requirement for Aromaticity 6 electrons 4 electrons 8 electrons notaromatic notaromatic aromatic
H H Completely Conjugated Polyenes 6 electrons;not completelyconjugated 6 electrons;completely conjugated notaromatic aromatic
Annulenes Annulenes are planar, monocyclic, completely conjugated polyenes. That is, they are the kind of hydrocarbons treated by Hückel's rule.
[10]Annulene Predicted to be aromatic by Hückel's rule,but too much angle strain when planar and all double bonds are cis. 10-sided regular polygon has angles of 144°.
van der Waalsstrain betweenthese two hydrogens [10]Annulene Incorporating two trans double bonds intothe ring relieves angle strain but introducesvan der Waals strain into the structure andcauses the ring to be distorted from planarity.
[14]Annulene 14 electrons satisfies Hückel's rule. van der Waals strain between hydrogens insidethe ring. H H H H
[16]Annulene 16 electrons does not satisfy Hückel's rule. Alternating short (134 pm) and long (146 pm) bonds. Is an antiaromatic 4np-electron system.
H H H H H H [18]Annulene 18 electrons satisfies Hückel's rule. Resonance energy = 418 kJ/mol. Bond distances range between 137-143 pm.
H H H H + H H H Cycloheptatrienyl Cation 6 electrons delocalizedover 7 carbons positive charge dispersedover 7 carbons very stable carbocation also called tropylium cation
H H H H H H H H + + H H H H H H Cycloheptatrienyl Cation
+ H Br Cycloheptatrienyl Cation Tropylium cation is so stable that tropyliumbromide is ionic rather than covalent. mp 203 °C; soluble in water; insoluble indiethyl ether Br– Ionic Covalent
H H •• H H – H Cyclopentadienide Anion 6 electrons delocalizedover 5 carbons negative charge dispersedover 5 carbons stabilized anion
H H H H – •• H H H H – H H Cyclopentadienide Anion
H H H H + H+ •• H H H H – H H H Acidity of Cyclopentadiene Cyclopentadiene is unusually acidic for a hydrocarbon. Increased acidity is due to stability of cyclopentadienide anion. pKa = 16 Ka = 10-16
H H H H – •• H H H H H H H H H H H H – •• – • – • • • H H H H H H H H H Electron Delocalization in Cyclopentadienide Anion •• –
H H H H H H H H H H H H H H H Compare Acidities ofCyclopentadiene and Cycloheptatriene pKa = 16 Ka = 10-16 pKa = 36 Ka = 10-36
H H H H H H •• H H – •• H H H H Compare Acidities ofCyclopentadiene and Cycloheptatriene – Aromatic anion 6 electrons Antiaromatic anion8 electrons
H H H H + + H H Cyclopropenyl Cation n = 0 4n +2 = 2 electrons also written as
Cyclooctatetraene Dianion H H H H n = 2 4n +2 = 10 electrons – H H H H •• alsowritten as 2– •• H H H H – H H H H
•• •• •• O S N N •• •• •• H Examples Pyridine Pyrrole Furan Thiophene
• N • N •• Examples Quinoline Isoquinoline
N •• Pyridine 6 electrons in ring. Lone pair on nitrogen is in ansp2 hybridized orbital;not part of system of ring.
•• N H Pyrrole Lone pair on nitrogen must be part of ring system if ring is to have6 electrons. Lone pair must be in a p orbitalin order to overlap with ring system.
•• O •• Furan Two lone pairs on oxygen. One pair is in a p orbital and is partof ring system; other is in an sp2 hybridized orbital and is notpart of ring system.