F = ma

1. (Mon) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a stein with a mass of 900 g with a force of 11.55 N from rest for 0.5 s, what will be the stein’s speed when he stops pushing? (10 min/5 pts)

2. (Mon) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a stein with a mass of 900 g with a force of 11.55 N from rest for 0.5 s, what will be the stein’s speed when he stops pushing? F = ma vf = vi + at a = F/m vf = 0.0 m/s + (12.83 m/s²)(0.5 s) a = 11.55 N / 0.9 kg vf = 6.42 m/s a = 12.83 m/s²

3. (Tue) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein so that it has a speed of 6.42 m/s on a frictionless bar 1 m tall, how far will the stein travel horizontally after it falls off the end of the bar? (10 min/5 pts)

4. (Tue) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein so that it has a speed of 6.42 m/s on a frictionless bar 1 m tall, how far will the stein travel horizontally after it falls off the end of the bar? In the “Y” direction In the “X” direction Δx = vi + ½at² Δx = vt 1.0 m 1m = 0m/s + (0.5)(-9.81m/s²)(t²) Δx = (6.42m/s)(0.45s) 6.42 m/s 0 m/s (1m)/(4.905m/s²) = t² Δx = 2.89 m 6.42 m/s 0.2 s² = t² 0.45 s = t 0 m/s² -9.81 m/s² 0.45 s 0.45 s

5. (Wed) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein with an initial speed of 6.42 m/s on a bar with a coefficient of friction of 0.3, how far will the stein travel before it stops? (10 min/10 pts)

6. (Wed) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein with an initial speed of 6.42 m/s on a bar with a coefficient of friction of 0.3, how far will the stein travel before it stops? Fg = ma F = ma Fg = (0.9 kg)(-9.81m/s²) F/m = a -8.83 N 0 N Fg = -8.83 N (-2.65N)/(0.9kg) = a Fn = -Fg 0 N 8.83 N -2.94 m/s² = a Ff = μFn vf² = vi² + 2aΔx -2.65 N 0 N Ff = (0.3)(8.83 N) Ff = 2.65 N -2.65 N 0 N 0 m/s = (6.42m/s)² + (2)(-2.94m/s²)(Δx) (-41.22 m²/s²)/(-5.88 m/s²) = Δx Δx = 7.0 m

7. (Thu) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein from rest to 6.42 m/s for 0.5 s, how much work did Bert do to push the stein? (8 min/5 pts)

8. (Thu) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein from rest to 6.42 m/s for 0.5 s, how much work did Bert do to push the stein? Method #1 Method #2 vf = vi + at W = ΔKE 6.42 m/s = 0 m/s + a(0.5 s) 12.84 m/s² = a W = KEf - KEi F = ma W = ½mvf² - ½mvi² F = (0.9kg)(12.84 m/s²) F = 11.556 N W = ½(0.9kg)(6.42m/s)² - 0 vf² = vi² +2aΔx (6.42m/s)² = (0m/s)² +(2)(12.84m/s²)Δx W = 18.55 J 1.605m = Δx W = Fd W = (11.556 N)(1.605 m) W = 18.55 J

9. (Fri) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. Ernie rigs the glass to leak soda to throw off Bert. If Bert pushes a 0.9 kg stein at 6.42 m/s at the start, and 0.4 kg soda leaks out, what is the final speed for the stein (assume frictionless bar)? (7 min/5 pts)

10. (Fri) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. Ernie rigs the glass to leak soda to throw off Bert. If Bert pushes a 0.9 kg stein at 6.42 m/s at the start, and 0.4 kg soda leaks out, what is the final speed for the stein (assume frictionless bar)? ρi = ρf m1v1 = m2v2 (0.9 kg)(6.42 m/s) = (0.5 kg)(v2) 11.56 m/s = v2

11. End of Week Procedures: • Add up all the points you got this week • Put the total number of points at the top of your page (out of 30 points) • List any dates you were absent (and why) • Make sure your name and period is on the top of the paper • Turn in your papers