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Chapter 5 Chemical Reactions and Quantities

Learn how to determine the mole-to-mole ratio between substances in a balanced chemical equation and use coefficients to write mole factors.

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Chapter 5 Chemical Reactions and Quantities

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  1. Chapter 5Chemical Reactions and Quantities Mole Relationships in Chemical Equations LecturePLUS Timberlake 99

  2. Mole-Mole Factors • Show the mole-to-mole ratio between two of the substances in a balanced equation • Use the coefficients of two substances in the equation LecturePLUS Timberlake 99

  3. Writing Mole Factors 4 Fe + 3 O2 2 Fe2O3 Fe and O2 4 mole Feand 3 mole O2 3 mole O24 mole Fe Fe and Fe2O34 mole Fe and 2 mole Fe2O3 2 mole Fe2O3 4 mole Fe O2 and Fe2O3 3 mole O2 and 2 mole Fe2O3 2 mole Fe2O3 3 mole O2 LecturePLUS Timberlake 99

  4. Learning Check S1 3 H2(g) + N2(g) 2 NH3(g) A. A mole factor for H2 and N2 is 1) 3 mole N22) 1 mole N2 3) 1 mole N2 1 mole H2 3 mole H2 2 mole H2 B. A mole factor for NH3 and H2 is 1) 1 mole H2 2) 2 mole NH3 3) 3 mole N2 2 mole NH3 3 mole H2 2 mole NH3 LecturePLUS Timberlake 99

  5. Solution S1 3 H2(g) + N2(g) 2 NH3(g) A. A mole factor for H2 and N2 is 2) 1 mole N2 3 mole H2 B. A mole factor for NH3 and H2 is 2) 2 mole NH3 3 mole H2 LecturePLUS Timberlake 99

  6. Chemical Calculations 4 Fe + 3 O22 Fe2O3 How many moles of Fe2O3 are produced when 6.0 moles O2 react? 6.0 mole O2 x 2 mole Fe2O3 = 4.0 mole Fe2O3 3 mole O2 LecturePLUS Timberlake 99

  7. Learning Check S2 4 Fe + 3 O2 2 Fe2O3 How many moles of Fe are needed to react with 12.0 mole of O2? 1) 3.00 mole Fe 2) 9.00 mole Fe 3) 16.0 mole Fe LecturePLUS Timberlake 99

  8. Solution S2 4 Fe + 3 O2 2 Fe2O3 12.0 mole O2 x 4 mole Fe = 16.0 mole Fe 3 mole O2 LecturePLUS Timberlake 99

  9. Learning Check S 3 4 Fe + 3 O2 2 Fe2O3 How many grams of O2 are needed to produce 0.400 mole of Fe2O3? 1) 38.4 g O2 2) 19.2 g O2 3) 1.90 g O2 LecturePLUS Timberlake 99

  10. Solution S 3 2) 19.2 g O2 0.400 mole Fe2O3 x 3 mole O2 x 32.0 g O2 2 mole Fe2O3 1 mole O2 = 19.2 g O2 LecturePLUS Timberlake 99

  11. Mass of A Reaction The reaction between H2 and O2 produces 13.1 g of water. How many grams of O2 reacted? Write the equation H2 (g) + O2 (g) H2O (g) Balance the equation 2 H2 (g) + O2 (g) 2 H2O (g) LecturePLUS Timberlake 99

  12. Organize data mole bridge 2 H2 (g) + O2 (g) 2 H2O (g) ? g 13.1 g Plan g H2O mole H2O mole O2 O2 Setup 13.1 g H2O x 1 mole H2O x 1 mole O2 x 32.0 g O2 8.0 g H2O 2 mole H2O 1 mole O2 = 11.6 g O2 LecturePLUS Timberlake 99

  13. Points to Remember 1. Read an equation in moles 2. Convert given amount to moles 3. Use mole factor to give desired moles 4. Convert moles to grams grams (given grams (desired) moles (given) moles (desired) LecturePLUS Timberlake 99

  14. Learning Check S 4 How many grams of O2 are need to react 50.0 grams of Na in the reaction 4 Na + O2 2 Na2O Complete the set up: 50.0 g Na x 1 mole Na x ________ x _______ 23.0 g Na LecturePLUS Timberlake 99

  15. Solution S 4 4 Na + O2 2 Na2O 505 g Na x 1 mole Na x 1 mole O2 x 32.0 g 23.0 g Na 4 mole Na 1 mole O2 = g O2 LecturePLUS Timberlake 99

  16. Learning Check S5 Acetylene gas C2H2 burns in the oxyactylene torch for welding. How many grams of C2H2 are burned if the reaction produces 75.0 g of CO2? 2 C2H2 + 5 O2 4 CO2 + 2 H2O LecturePLUS Timberlake 99

  17. Solution S5 2 C2H2 + 5 O2 4 CO2 + 2 H2O 75.0 g CO2 x 1 mole CO2 x 2 mole C2H2 x 26.0 g C2H2 44.0 g CO2 4 mole CO2 1 mole C2H2 = 22.2 g C2H2 LecturePLUS Timberlake 99

  18. Pathways for Problems Using Equations Given (A) Find (B) grams (A) grams (B) moles (A) moles (B) particles (A)particles (B) LecturePLUS Timberlake 99

  19. Pathways for Problems Using Equations Given (A) Find (B) grams (A) grams (B) molar molar mass (A) mass (B) coefficients moles (A) moles (B) Avogadro's Avogradro’s number number particles (A)particles (B) LecturePLUS Timberlake 99

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