The dreaded “popcorn” problem … This is a 2 step problem

1. Step 1 • “Popcorn kernels pop unimolecularly…” • The dreaded “popcorn” problem… • This is a 2 step problem = first-order reaction ln(A) -ln(A0) = -kt determine k first • 29 kernels pop in 10 seconds when 400 total kernels are present. After 100 have popped, how many will pop over the next 10 seconds? • 29 kernels pop in 10 seconds when 400 total kernels are present.After 100 have popped, how many will pop over the next 10 seconds? • A0 = 400(initial number of kernels) • t = 10 sec • A = 371 (number of kernels at time t) • k = 0.00753 sec-1

2. Step 2 • Start over with a new initial condition • 1st ORDER: ln(A) -ln(A0) = -kt • and k = 0.00753 sec-1 • After 100 have popped, how many will pop over the next 10 seconds? • A0 = 300(initial number of kernels) • t = 10 sec • k = 0.00753 sec-1 • Answer: 300-278.25 = 22.75