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Determination of The Winners of 2012 Thomson Medal Award. The 1 st round voting will be held to select the top 9 candidates by the members of the IMSF Governing Committee ( Deadline for determining nine candidates is: 31 December, 2011)
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Determination of The Winners of 2012 Thomson Medal Award • The 1st round voting will be held to select the top 9 candidates by the members of the IMSF Governing Committee (Deadline for determining nine candidates is: 31 December, 2011) • The sponsors of the top 9 candidates submit additional information on the candidates’ achievements. The 2nd round voting by the members of the IMSF Governing Committee will be held to select the top three as the winners of 2012 Thomson Medal Award. (Deadline for determining three award winners is: 30 April, 2012)
Rules of The 1st Round Voting • Each IMSF affiliate should select exactly 9 candidatesamong the 20 nominees. The candidates must be ranked from 1 to 9 based on the priority determined by your society. 2. Make sure the candidate with the first number is your top priority (write number 1 in front of candidate’s name on the ballot) and the candidate with the last number (number 9) is your last choice. Every number of 1 to 9 should be used only for “one time”. 3. The votes collected from all IMSF affiliates will be used to determine the top 9 candidates by using the Hare system.
How to vote ? Put the number ‘1’ in front of the name of your top priority, put the number ‘2’ in front of the name of your second choice, the number ‘3’ in front of the name of your third choice, and so on until you have chosen 9 candidates. Please see the example as below: 1 Jones David John 7 Smith Cleaver 2 Brown 5 Black Yellow 3 Green9 Grey4 Wood6 Stone Rock8Clark Etc.
The ballot is invalid for the following situations: (a) More than 9 nominees are chosen. (b) Less than 9 nominees are chosen. (c) A number is given to more than one candidates. (d) A combination of any two or three on above. (e) A ballot received after December 22, 2011. 1 Jones David John 7 Smith Cleaver 1 Brown 5 Black Yellow 1 Green9 Grey4 Wood 6 Stone Rock8Clark Etc. (a) 1 Jones 11David John 7 Smith Cleaver 2 Brown 5 Black Yellow 3 Green9 Grey4 Wood6 Stone 10Rock8Clark Etc. (b) 1 Jones David John 7 Smith Cleaver 2 Brown 5 Black Yellow 3 Green Grey4 Wood6 Stone RockClark Etc. (c)
Please e-mail your ballot (with 9selected candidates who have been ranked from 1 to 9) to Prof. Jentaie Shiea (jentaieshiea@gmail.com) by December 22, 2011. The vote counting will start after December 22, 2011.
Counting of the Ballots – The Hare System • The Hare System is intended to secure the representation of every shade of the electorate’s opinion in direct proportion to its numerical strength. • Therefore, the order of voter’s preference is very important to every candidate due to the transfer of votes.
Counting of the Ballots: The Quota • The first step in counting the ballots is to determine the number of the first choice necessary to elect a candidate. This is obtained by the following formula: the number of votes cast the number to be elected + 1 + 1 = quota For example, in an election in which there were 425 votes cast in balloting to elect 17 members on one ballot, the quota will be: 425 17 + 1 +1 = 24 Remaining options are always discarded. The quota of 24 represents the least number of first choices a candidate may receive and still be declared elected. The extra "1" is added (after the division) because, without it, the quota would be 23, making it possible for 18 candidates each to receive 23 votes, when only 17 are to be elected.
Counting of the Ballots • The ballots are divided into piles according to the first choices indicated. It will then be found, we may suppose, that 27 have marked Jones as the first choice, that 26 have marked Brown as first choice, etc. In tabular fashion, the results might be as follows, according to the first choices marked: Jones & Brown are elected Quota: 24 27 Jones26 Brown22 Green22 Wood 14 Black
Transferring of Votes • Jones and Brown, having secured the quota of 24, are declared elected. • Jones has 3 more votes than needed for election. As these three ballots can no longer help Jones to be elected, they are transferred to help elect other candidates. Thus, the three ballots (randomly selected from 27 votes) are transferred to the second choices indicated on each. If any of these second choices are for Brown, who also has already been elected, the third choice is given the ballot instead. • Brown’s extra votes (i.e., those in excess of 24), are then distributed according to second choice, etc.
Examples of Transferring Votes Two votes randomly selected from 26 votes (Brown): Three votes randomly selected from 27 votes (Jones): • Jones has three more votes, and Brown has two more votes to transfer. 1 Jones 3 Brown 5 Black 2 Green4 Wood……......... 1 Jones 2 Brown 5 Black 4 Green3 Wood ……......... 1 Jones 4 Brown 2 Black 3 Green5 Wood ……......... 3 Jones 1 Brown 5 Black 4 Green2 Wood ……......... 4 Jones 1 Brown 5 Black 3 Green2 Wood ……......... Wood is elected after transferring of votes Quota: 24 The vote is transferred to Wood because Brown has already been elected. The vote is transferred to Black. The vote is transferred to Wood. The vote is transferred to Wood. The vote is transferred to Green. Below is the result after transferring of votes: 24 Jones24 Brown25 Wood 23 Green16 Black ………… …………. 27 Jones26 Brown22 Green22 Wood 15 Black………………....... Keep transferring until the 9 candidates have been selected. First Transferring