1 / 22

Acids & Bases

Acids & Bases. Calculating Ka from % Dissociation Polyprotic Acids Properties of Salts. Example. Lactic acid (HC 3 H 5 O 3 ) is a waste product that accumulates in the muscle during exertion, leading to pain & a feeling of fatigue. A 0.100 M solution is 3.7% dissociated. Calculate K a.

emmet
Download Presentation

Acids & Bases

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Acids & Bases Calculating Ka from % Dissociation Polyprotic Acids Properties of Salts

  2. Example • Lactic acid (HC3H5O3) is a waste product that accumulates in the muscle during exertion, leading to pain & a feeling of fatigue. A 0.100 M solution is 3.7% dissociated. Calculate Ka.

  3. Example HC3H5O3  H+ + C3H5O3-

  4. Polyprotic Acids • More that one ionizable H+ • H+ come off one at a time • Each one has a specific Ka value • Ka1>>>>Ka2>>Ka3 • When calculating the pH of a polyprotic acid, you only use the 1st Ka because all of the others are so small

  5. Complete Ionization • Write the steps for the complete ionization of H2Se

  6. Complete Ionization • Write the steps for the complete ionization of H3AsO

  7. Example • Calculate the pH & the [ ] of all species of a 3.0 M solution of H3PO4. • Ka1 = 7.5 x 10-3, Ka2 = 6.2 x 10-8, Ka3 = 4.8 x 10 -13

  8. Example H3PO4 H+ + H2PO4- Ka1 = 7.5 x 10-3

  9. Example H2PO4 - H+ + HPO4-2 Ka1 = 6.2 x 10-8

  10. Example HPO4 -2 H+ + PO4-3 Ka3 = 4.8 x 10-13

  11. Example • pH = • [H3PO4] = • [H2PO4-] = • [HPO4-2] = • [PO4-3] = • [H+] =

  12. Acid Base Properties of Salts • Salts of weak acids produce basic solutions • NaC2H3O2

  13. Acid Base Properties of Salts • Salts of weak bases produce acidic solutions • NH4Cl

  14. Acid Base Properties of Salts • Salts of strong acids & Bases produce neutral solutions • NaCl

  15. Calculations with salts • KaxKb = Kw • Can find Ka or Kb with this equation • On AP formula sheet

  16. Example • What is the pH if a 0.140M solution of NaC2H3O2 (KaHC2H3O2 = 1.8x10-5)

  17. Another example • What is the pH of a 0.140M solution of diethylaminochloride (C2H5)2NH3Cl. • Kb (C2H5)2NH3+ = 1.3x10-3 • (C2H5)2NH3Cl  (C2H5)2NH3+ + Cl- • (C2H5)2NH3+ + H2O  (C2H5)2NH2 + H3O +

  18. Qualitative Predictions of pH • Ka>Kb  acidic • Kb>Ka  basic • Ka = Kb  neutral

  19. pH Predictions • Predict if an aqueous solution of the following are acidic, basic, or neutral • NH4C2H3O2 • Kb NH4+ = 1.8x10-5 • Ka HC2H3O2 = 1.8x10-5

  20. pH Predictions • Predict if an aqueous solution of the following are acidic, basic, or neutral • NH4CN • Kb NH4+ = 1.8x10-5 • Ka HCN= 6.2x10-10

  21. Effect of Structure of Acid Base Properties • Weak acid (HF) • Stays together • Strong acids • Look at electronegativity

  22. Effect of Structure of Acid Base Properties

More Related