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Geomath. Geology 351 -. Differential Calculus. tom.h.wilson tom.wilson@mail.wvu.edu. Dept. Geology and Geography West Virginia University. Derivative concepts. Refer to comments on the computer lab exercise. Between 1 and 2 kilometers the gradient is -0.12 km -1.
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Geomath Geology 351 - Differential Calculus tom.h.wilson tom.wilson@mail.wvu.edu Dept. Geology and Geography West Virginia University
Derivative concepts Refer to comments on the computer lab exercise.
As we converge toward 1km, /z decreases to -0.14 km-1 between 1 and 1.1 km depths.
What is the gradient at 1km? What is ?
The power rule - The book works through the differentiation of y = x2, so let’s try y =x4. multiplying that out -- you get ...
Remember the idea of the dy and dx is that they represent differential changes that are infinitesimal - very small. So if dx is 0.0001 (that’s 1x10-4) then (dx)2 = 0.00000001 (or 1x10-8) (dx)3 = 1x10-12 and (dx)4 = 1x10-16. So even though dx is very small, (dx)2 is orders of magnitude smaller
Divide both sides of this equation by dx to get This is just another illustration of what you already know as the power rule,
which - in general for is Just as a footnote, remember that the constant factors in an expression carry through the differentiation. This is obvious when we consider the derivative -
The sum rule - Given the function - what is ? We just differentiate f and g individually and take their sum, so that
Product and quotient rules - Recall how to handle derivatives of functions like or ?
Removing explicit reference to the independent variable x, we have Going back to first principles, we have Evaluating this yields Since dfdg is very small and since y=fg, the above becomes -
The quotient rule is just a variant of the product rule, which is used to differentiate functions like Which is a general statement of the rule used to evaluate the derivative of a product of functions.
The Chain Rule - Differentiating functions of functions - Given a function we consider write compute Then compute and take the product of the two, yielding
Outside to inside rule We can also think of the application of the chain rule especially when powers are involved as working form the outside to inside of a function
Where Again use power rule to differentiate the inside term(s) Derivative of the quantity squared viewed from the outside.
Using a trig function such as let then Which reduces to or just
In general if then
Returning to those exponential and natural log cases - we already implemented the chain rule when differentiating h in this case would be ax and, from the chain rule, becomes or and finally since and
For functions like we follow the same procedure. From the chain rule we have Let and then hence
Thus for that porosity depth relationship we were working with -
For logarithmic functions like We combine two rules, the special rule for natural logs and the chain rule. Log rule then Let Chain rule and so
The quotient rule states that And in most texts the proof of this relationship is a rather tedious one. The quotient rule is easily demonstrated however, by rewriting the quotient as a product and applying the product rule. Consider
We could let h=g-1 and then rewrite y as Its derivative using the product rule is just dh = -g-2dg and substitution yields
Multiply the first term in the sum by g/g (i.e. 1) to get > Which reduces to i.e. the quotient rule
Special Cases- Given > • The derivative of an exponential function In general for If express a as en so that then Note
Take a few moments to through the examples on your worksheet
For next time look over question 8.8 in Waltham (see page 148). Find the derivatives of
Finish reading Chapter 8 Differential Calculus