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Solving systems of equations and inequalities by graphing. Systems of equations. Remember that a system of equations is a group of two or more equations that we solve at the same time
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Systems of equations • Remember that a system of equations is a group of two or more equations that we solve at the same time • A point is a solution of the system if it works when substituted into each equation. For example, the solution to the system above is (2,0).
Review of graphs of systems of linear equations • When working with two equations in two variables, there are three possibilities for their graphs: The lines can intersect and have one solution (x, y). The lines can be parallel and have no solution. The lines can coincide and have infinitely many solutions.
But now… • We want to start working with systems that don’t just have linear equations. • We will still graph our functions and look for the point(s) of intersection when we want to solve our systems.
EXAMPLE 1 • Let’s solve the system below by graphing: • Graph each function on the same coordinate plane:
EXAMPLE 1 CONTINUED • Look at the graph and identify the points of intersection: There are two points of intersection, so our system has two solutions: (-1, 2) and (1, 2) You can substitute both points into your equations and get true statements. This is an easy way to check your work!
To solve using your calculator • Put your equations in y =. abs( can be found by pressing 2nd 0, and choosing the first option. • Graph to see the number of solutions.
To solve using your calculator…continued • To find the first point of intersection, press 2nd TRACE, and choose #5 (intersect). Move your cursor to the left of the first intersection and press enter. Move to the right and press enter. Then press enter a third time to see the coordinates: • Repeat the process to find the second solution at (1, 2).
EXAMPLE 2 • Let’s solve: • First, recognize that the first equation is an absolute value graph (a V) that has been shifted right 2 units and down 1 unit. • Then, solve the second equation for y: y = x + 1. • Finally, graph.
Example 2 continued • The graphs intersect ONCE. • The only solution to the system is (0, 1). • Notice that you can substitute your point into both equations and get a true statement.
EXAMPLE 3 • Let’s solve: • First, solve the first equation for y to get . Then, recognize that this is an absolute value graph (a V) that has been shifted left 2 units, down 2 units, and reflected across the x-axis. • The second equation is a line. • Now, graph.
Example 3 continued • The graphs don’t intersect. • The solution is that there is no solution. • This means there is NO point that exists that would give you a true statement for both equations.
Summary of steps • Graph each function in your system. It would be most helpful if you solve for y in each case. • Identify the point(s) of intersection of the graphs of your functions. • State your solution(s). Check them by substituting back into your system of equations.
Systems of INEQUALITIES • Remember that a system of inequalities is a group of two or more equations that we solve at the same time: • Here’s a review of what the symbols tell us to do: • >: dashed line, shaded above boundary line • <: dashed line, shaded below boundary line • : solid line, shaded above boundary line • : solid line, shaded above boundary line
Systems of Inequalities Continued • We will graph each boundary line just as we did before, and we will put each of them on the same coordinate plane. • Where the shaded regions all overlap will represent the solution of our system—meaning that any point from the shared region will produce a true solution when substituted into all of the inequalities in our system
EXAMPLE 1 • Let’s solve the system below by graphing: • The first will be a dashed line shaded above. (in red) • The second will be a solid line shaded below. (in blue) • Graph each inequality on the same coordinate plane. The area where they overlap is the solution.
EXAMPLE 1 CONTINUED • The region where both shaded areas overlap represents the solution to our system. Notice the region occurs in both Quadrant II and in Quadrant III. • Any point chosen from this area will produce true statements when substituted into both inequalities.
Example 2 • Solve the system by graphing: • The first is an absolute value function; use a solid line and shade above. (in red) • The second is a horizontal line; use a dashed line and shade below. (in blue) • Since the shaded regions don’t overlap, this system has no solution.
Example 3 • Solve the system by graphing: • The first is a vertical line. Use a solid line and shade to the right. • The second is a vertical line. Use a solid line and shade to the left. • The third is a diagonal line. Solve for y. Then use a solid line and shade below. • The solution region is shaded the darkest.
Up next… • In Lessons 4 and 5, you will study a real-world application of solving systems of linear equations and inequalities!