1 / 12

Projectiles at an Angle

Projectiles at an Angle. Physics Mrs. Coyle. Projectiles at an Angle. Projectiles at an Angle. http://www.physicsclassroom.com. Projectiles at an Angle. Motion in two dimensions x-axis constant velocity y-axis constant acceleration Parabolic trajectory. Initial Velocity. v xi =vcos q

errin
Download Presentation

Projectiles at an Angle

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Projectiles at an Angle Physics Mrs. Coyle

  2. Projectiles at an Angle

  3. Projectiles at an Angle http://www.physicsclassroom.com

  4. Projectiles at an Angle • Motion in two dimensions • x-axis constant velocity • y-axis constant acceleration • Parabolic trajectory

  5. Initial Velocity • vxi=vcosq • vyi=vsinq v

  6. A Look at the Velocities

  7. Equations for Projectiles at an Angle • Initial Velocity is at an angle with the horizontal • vx=constant • vy=vyi+at a=-10m/s2 • Dy=vyit+ 1at2 2

  8. Additional Key Points • At the max height: vy=0 vx=constant=vxi • Maximum range when q=45 degrees in the absence of air resistance. • Complementary angles result in the same range. • Symmetry • Resultant velocity is tangent to the curve at the point of study.

  9. Demonstration Link Projectiles at an Angle

  10. Example 1 An arrow is shot with an initial x velocity of 5m/s and an initial y velocity is 15m/s. • How much time will pass for the projectile to reach max height? • What is the max height? • What is the range? Answer: a) t=1.5s , b)y= 11.25m, c) x=15m

  11. Example 2 A cannonball is shot with an initial x velocity of 60m/s and an initial y velocity of 25m/s. a)What is the max height? b)What is the range?Answer: a) t=2.5s, y=31.25m b) x=300m

  12. Example 3 Using vx=vcosq, vy=vsinq A cannonball is shot at 60 degrees with an initial velocity of 40m/s. a)What is the max height? b)What is the range? c)At what angle should the projectile be shot to achieve max range and what is the max range? a)Vx=20m/s, Vy=34.64m/s, t max=3.5s, y=61mb) 140m, c) 45o , 163m

More Related