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Warm Up 1. Which pair of factors of 8 has a sum of 9? 2. Which pair of factors of 30 has a sum of –17? Multiply. 1 and 8. –2 and –15 . 3. (x +2)(x +3) . x 2 + 5 x + 6. 4. ( r + 5)( r – 9). r 2 – 4 r – 45. Simplify. c. Learning Target.
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Warm Up 1. Which pair of factors of 8 has a sum of 9? 2. Which pair of factors of 30 has a sum of –17? Multiply. 1 and 8 –2 and –15 3. (x +2)(x +3) x2 + 5x + 6 4. (r + 5)(r– 9) r2 – 4r – 45
Simplify. c.
Learning Target Students will be able to: Factor quadratic trinomials of the form x2 + bx + c.
Factor each trinomial by guess and check. x2 + 10x + 24
Factor each trinomial by guess and check. x2 + 7x + 12
Factor each trinomial. Check your answer. x2 + 6x + 5
Factor each trinomial. Check your answer. x2 + 6x + 9
Factor each trinomial. Check your answer. x2– 8x + 15
Factor each trinomial. Check your answer. x2– 5x + 6
Factor each trinomial. Check your answer. x2 + 13x + 42
Factor each trinomial. Check your answer. x2– 13x + 40
Factor x2 + x– 20
Factor each trinomial. x2– 3x– 18
Factor each trinomial. Check your answer. x2 + 2x– 15
Factor each trinomial. Check your answer. x2– 6x + 8
Factor each trinomial. Check your answer. X2– 8x– 20
A polynomial and the factored form of the polynomial are equivalent expressions. When you evaluate these two expressions for the same value of the variable, the results are the same.
Factor y2 + 10y + 21. Show that the original polynomial and the factored form have the same value for y = 0,1, 2, 3,and 4.
y (y + 7)(y + 3) y2 + 10y + 21 y (0 + 7)(0 + 3) = 21 0 02 + 10(0) + 21 = 21 0 1 (1 + 7)(1 + 3) = 32 12 + 10(1) + 21 = 32 1 2 (2 + 7)(2 + 3) = 45 22 + 10(2) + 21 = 45 2 3 3 32 + 10(3) + 21 = 60 (3 + 7)(3 + 3) = 60 (4 + 7)(4 + 3) = 77 4 42 + 10(4) + 21 = 77 4 Evaluate the original polynomial and the factored form for y = 0, 1, 2, 3, and 4. The original polynomial and the factored form have the same value for the given values of n.