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PHY 320 Intermediate Physics Laboratory II

PHY 320 Intermediate Physics Laboratory II. Important items of business. 1. Go to course web site to print copy of syllabus; review syllabus 2. All PHY 320 students are required to conduct the experiment that measures the half-life of a radionuclide; safety matters discussed today.

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PHY 320 Intermediate Physics Laboratory II

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  1. PHY 320 Intermediate Physics Laboratory II Important items of business

  2. 1. Go to course web site to print copy of syllabus; review syllabus • 2. All PHY 320 students are required to conduct the experiment that measures the half-life of a radionuclide; safety matters discussed today. • 3. Instructor will provide oral critiques of drafts of reports. • 4. Note due dates and times for reports in syllabus: Caution: You should insure the functionality of the apparatus for any experiment long prior to conducting it.

  3. 11 Apr Individual Presentations1: Brown, Frost, Gallis, Larkin, Lawton 18 Apr Individual Presentations1: LeGalle, Lechner, Massaro, Mayer, McCauley 25 Apr Individual Presentations1: Savoy, Sheriff, Snyder, Sutton, Zeits

  4. 2 May Group Presentations2 2 Group presentations are assigned as follows: 1. Zeeman Effect: Brown, Frost, Gallis, Larkin, Lawton 2. Nuclear Spectroscopy: LeGalle. Lechner, Massaro, Mayer, McCauley 3. Hall Effect: Savoy, Sheriff, Snyder, Sutton, Zeits

  5. 21 Mar Panel discussion on Shroud of Turin data, 3:00 p.m. Format: Oral arguments before the Supreme Court Class members to be divided into two groups: Defend paper in Nature Challenge paper in Nature Note: Paper in Nature restricts itself to dating the artifact.

  6. Faulty Assumption: Scientists and the research papers they publish are free of errors and biases. … a different example from Nature

  7. 1 Sverdrup (Sv) = 106 m3/sA measure of volume of water transport. Benchmark: The entire global input of fresh water from rivers to the oceans is equal to about 1 Sv.

  8. Q: Is 23 ± 6 significantly different from or inconsistent with 15 ± 6?

  9. How did the authors obtain the “about 30 percent” quoted in the abstract? (22.9 – 14.8)/22.9 = 0.353 (23 – 15)/23 = 0.35 Why did the authors not compute the change as (23 – 15)/15 = 0.53 ?

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