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E = mc 2 # 4

Balancing Equations. E = mc 2 # 4. Balance the following equation and identify the type of reaction. 1. __ BaBr 2 + __ K 2 SO 4  __KBr + __BaSO 4 2. __ Na + __ H 2 O  __ NaOH + __H 2 What type of bond would you expect KBr to have? Why? How about H 2 O?. Answers.

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E = mc 2 # 4

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  1. Balancing Equations E = mc2 # 4

  2. Balance the following equation and identify the type of reaction. • 1. __ BaBr2 + __ K2SO4 __KBr + __BaSO4 • 2. __ Na + __ H2O  __ NaOH + __H2 • What type of bond would you expect KBr to have? Why? • How about H2O?

  3. Answers • 1. 1 BaBr2 + 1 K2SO4 2 KBr + 1 BaSO4 • Double Displacement • 2. 2 Na + 2 H2O  2 NaOH + 1H2 • Single Displacement • What type of bond would you expect KBr to have? • Ionic • Why? K and Br are on opposite sides of the periodic table • How about H2O? Polar covalent

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