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Corrections 143-146

Corrections 143-146. Page 143. 1) a) $1.5/year  the value increases by $1.5 per year B) $0 /year  the value remained constant C) $- 6/year  the value decreased by $6 per year 2) a) y = 15 B) horizontal line through y = 15 C) constant or zero variation. Page 143. 3) A) y = 30x

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Corrections 143-146

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  1. Corrections 143-146

  2. Page 143 • 1) a) $1.5/year  the value increases by $1.5 per year • B) $0 /year  the value remained constant • C) $- 6/year  the value decreased by $6 per year • 2) a) y = 15 • B) horizontal line through y = 15 • C) constant or zero variation

  3. Page 143 • 3) • A) y = 30x • C) direct variation

  4. Page 144 • 4) • A) y = 10x + 15 • c) Partial variation • 5) a) y = 1200 / x

  5. Page 144 • 6. a) $15 • B) 120 • C) y = 15x – 120 • D) 1. less than 8 2. More than 8 • 7) a) 15 000 Litres (find a and b values, write rule, then set x equal to7 hours) y = -5000 x + 50 000 • B) 10 hours (replace y with 0)

  6. Page 145 • 8 a) independent: time • Dependent: volume of water in the tank • B) y = -5t + 80 • C) 1. replace y with 0 and solve for t  16 hours • 2. the graph hits the x axis (where y = 0) at t = 16 hours

  7. Page 145 • 9) • A) A: y = 300 B: y = 10x C: y = 5x + 100 • B) A: zero B: direct C: Partial • D) if the employee sells less than 30 items • E) if the employee sells more than 30 items • F) c is never the best option (it never has the greatest y value)

  8. Page 145 • 10) x = # of videos y = cost • A: y = 2.5x + 10 • B: y = 3x • Use comparison to see how many videos it would take before the cost is the same • 3x = 2.5x + 10  x = 20 videos • If you rent more than 20 videos per year, option A is better. Less than 20, option B is better

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