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Molarity Notes. Formulas. M 1 V 1 = M 2 V 2. Example 1:. If a beaker containing a 4.0 M solution goes from 35 mL to 65 mL, what is the new concentration?. Example 2:. What is the molarity of a solution containing 5.0 moles of KOH in 300 mL of solution?. Example 3:.
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Formulas • M1 V 1 = M2V 2
Example 1: • If a beaker containing a 4.0 M solution goes from 35 mL to 65 mL, what is the new concentration?
Example 2: • What is the molarity of a solution containing • 5.0 moles of KOH in 300 mL of solution?
Example 3: • A solution contains 350 grams of CaCl2 and • 5.0 Liters of water, what is the molarity of this solution?
Molarity Practice • You will need… • White board • Marker • Towel
Question 1: • What is the molarity of a solution that contains • 105.0 g of NaNO3in 2.00 L of solution?
Question 2: • What is the molarity of a solution containing • 2.0 moles of potassium phosphate in 400. mL?
Question 3: • If 700 mL of a 4.5 M solution of NaBr is diluted to 2.0 M, what is the final volume of the solution?
Question 4: • What is the molarity of a solution that contains 9.5 moles of CaCl2 in 4.00 L of solution?
Question 5: • A student has 50 mL of a 3.2 M solution of an acid. He adds water until he has 85 mL of the solution. What is the new concentration?
Question 6: • What is the molarity of a solution composed of 5.85g of potassium iodide (KI) dissolved in enough water to make 0.125 L of solution?