1 / 9

5.8 Applications of Quadratic Equations

5.8 Applications of Quadratic Equations. Steps (reviews). Read and underline important words and numbers Assign variables Create equation and solve equation Check State answer. Problem with Geometric Figures.

forest
Download Presentation

5.8 Applications of Quadratic Equations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 5.8 Applications of Quadratic Equations

  2. Steps (reviews) • Read and underline important words and numbers • Assign variables • Create equation and solve equation • Check • State answer

  3. Problem with Geometric Figures 1) The length of a hall is five times the width. The area of the floor is 45m2. Find the length and width of the hall.

  4. 5w • 1) The length of a hall is five times the width. The area of the floor is 45m2. Find the length and width of the hall. • Equation: w (5w) = 45 5w2 = 45 w2 = 9 w2 – 9 = 0 (w-3)(w+3) = 0 w = 3 or w = -3 w THEREFORE: The width is 3m and the length is 5(3) = 15m Impossible to have negative width so discard this answer

  5. Problem with consecutive numbers 2) The product of the smallest and largest of three consecutive odd integers is 16 more than the middle integer. Find the numbers.

  6. The product of the smallest and largest of three consecutive odd integers is 16 more than the middle integer. Find the numbers. Let x, x+2, x+4 are three consecutive odd integers Equation: x (x+4) = (x+2) + 16 x2 + 4x = x + 2 + 16 x2 + 4x = x + 18 x2 + 4x – x – 18 = 0 x2 + 3x – 18 = 0 (x + 6) (x -3) = 0 x = -6 or x = 3 Therefore, the numbers are 3, 5, 7 -6 is an even number so discard this answer

  7. 4) If an object is propelled upward from ground level with an initial velocity of 64 ft per sec, its height h in feel t seconds later is h = -16 t2 + 64t • After how many seconds is the height 48ft • After how many seconds does the object hit the ground?

  8. 48 = -16t2 + 64t -3 = t2 – 4t (divide both sides by -16) t2 – 4t + 3 = 0 (t- 3) (t-1) = 0 t = 3 or t = 1 Therefore, the height is 48 ft after 1 second or after 3 seconds b) 0 = -16t2 + 64t 0 = t2 – 4t (divide both sides by -16) 0 = t (t – 4) t = 0 or t = 4 Therefore, the object hits the ground after 4 seconds.

  9. Pythagorean Formula a2 + b2 = c2 Hypotenuse c Leg a Leg b

More Related