1 / 16

Lecture 32

Lecture 32. Review: AC power analysis Average power, complex power, power triangles RMS values Power factor Power factor correction Related educational materials: Chapter 12.5, 12.6. AC power analysis. Average power: Average power in terms of RMS (or effective) values: Complex power:.

fpage
Download Presentation

Lecture 32

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Lecture 32 Review: AC power analysis Average power, complex power, power triangles RMS values Power factor Power factor correction Related educational materials: Chapter 12.5, 12.6

  2. AC power analysis • Average power: • Average power in terms of RMS (or effective) values: • Complex power:

  3. Power triangles • Complex power (rectangular form): • Real (average) and reactive power: • Presented graphically:

  4. Power factor (pf) • Power factor: • Load impedance:

  5. Example 1 For the circuit below, determine: (a) the complex power delivered by the source (b) the average power delivered by the source

  6. Outline problem on previous slide: • 1. find equivalent impedance • 2. find source current • 3. complex power = VI*/2 • 4. Average power = (Vm*Im/2)*cos(thetav-thetai)

  7. (a) Determine the complex power delivered by the source

  8. (b) Determine the average power delivered by the source

  9. Effect of pf on power delivery • If v - i 0, we have some reactive power that is not consumed by the load • The current provided to the load is higher than necessary • Results in additional power dissipated during delivery • Power companies don’t like this!

  10. Power factor correction • Power companies may require that users maintain a minimum power factor • e.g. pf > 0.9 • Most large loads are inductive in nature • e.g. inductive motors • Power factor correction may be necessary • The approach must be inexpensive & simple to implement • Adding a capacitor in parallel with the inductive load will increase the power factor

  11. Power factor correction – continued • We have an inductive load with some power factor cos1: • The power triangle is shown below:

  12. Power factor correction – continued again • We can increase the power factor by adding a capacitor in parallel with the load: • The power triangle then becomes:

  13. Example 2 – power factor correction For the circuit below if (a) Determine the power factor (b) Re-design the circuit so that pf = 1

  14. Example 2 – Determine pf

  15. Example 2 – Re-design circuit so that pf = 1

More Related