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Lecture 2

Lecture 2. Intro to Spectroscopy NMR Spectroscopy: How it works Chemical Shift in 1 H NMR Equivalent & Non-equivalent Hydrogens. Organic Chemistry: From Yesterday to Today. 1800’s: Organic Structural Theory - Combustion Analysis - Functional Group Tests. Late 1700’s: Atomic Theory.

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Lecture 2

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  1. Lecture 2 • Intro to Spectroscopy • NMR Spectroscopy: • How it works • Chemical Shift in 1H NMR • Equivalent & Non-equivalent Hydrogens

  2. Organic Chemistry: From Yesterday to Today 1800’s: Organic Structural Theory - Combustion Analysis - Functional Group Tests Late 1700’s: Atomic Theory 1900’s: Synthesis and Analysis Today:Automated Synthesis & Spectroscopic Analysis

  3. Spectral Analysis Each type of spectral analysis has its value in determining/confirming the structure of a compound. Spectroscopy allows us to “see” the molecule. NMR (Nuclear Magnetic Resonance) Spectroscopy: • Different types of nuclei in a molecule (1H & 13C) • 1H NMR: Aids in the determination of bond connectivity within a molecule & the pieces of a molecule IR (Infrared) Spectroscopy: • Confirms the presence of functional groups within a molecule MS (Mass Spectrometry): • Determines the mass of a compound • Also aids in the determination of pieces of the molecule

  4. Types of Analysis NMR (Nuclear Magnetic Resonance Spectroscopy): • Uses radio waves (electromagnetic radiation) • Interacts with sample’s nuclei in the presence of a magnet • Effect: nuclei flip and relax (known as resonance) IR (Infrared Spectroscopy) • IR radiation • Interacts with molecule as a whole • Effect: bond vibrations within molecule MS (Mass Spectrometry) • No radiation used • Interacts with and destroys molecule; fragments molecule • Effect: creates ions and neutral fragments of molecule

  5. 1H NMR Spectrum of Ethanol CH3CH2OH ppm

  6. IR Spectrum of Hexanol % Transmittance Wavenumber (cm-1)

  7. Mass Spectrum of Phenetole 94 Intensity 122 77 m/z (mass to charge ratio)

  8. Nuclear Magnetic Resonance Use: To assist in the elucidation of a molecule’s structure Information Gained: • Different chemical environments of nuclei being analyzed (1H nuclei): chemical shift • The number of nuclei with different chemical environments: number of signals in spectrum • Determine the number of protons that are adjacent to one another: splitting patterns • The numbers of protons with the same chemical environment: integration • Determine how many protons are bonded to the same carbon: integration • Determine which protons are adjacent to one another: coupling constants

  9. How does NMR work? Basic Idea: In the presence of an applied magnetic field (Bo) - the NMR instrument: • Irridate the sample with radiofrequency radiation 2. Nuclei resonance: excite magnetic transitions 3. Measure the energy absorbed/released by nuclei 4. Obtain a spectrum

  10. How does NMR work? Facts that allow NMR to work: • Nuclei have a spin (like electrons). • Nuclei that have odd mass or odd atomic number have a quantized spin angular momentum and a magnetic moment. • The allowed spin states a nucleus can adopt is quantized and is determined by its nuclear spin quantum number, I. 1H and 13C nuclei have I = 1/2. Thus, there are two allowed spin states: +1/2 and -1/2.

  11. 1H NMR Spectroscopy • 1H nuclei have magnetic spin, I = 1/2. • The nuclei can either align with (+1/2) or oppose (-1/2) the applied magnetic field, Bo (from the NMR instrument). • When the nuclei absorb the radiofrequency pulse (a specific energy is absorbed since the spin states are quantized!), the spin flips - resonance. • When the pulse is over, the spin relaxes back to its original state. The spin releases the energy that it had originally absorbed - this is the energy that is measured. This happens to each 1H nuclei in the sample, but not every 1H nuclei are the same.

  12. How does NMR work?

  13. Getting a Spectrum • Pulse sample with radiofrequency radiation, spin flip - resonance. • After pulse, the excited nuclei lose their excitation energy and return to • their original state - relax. • As the nuclei relax, they emit electromagnetic radiation; results in • free-induction decay (FID) • FID contains all emitted frequencies: • Fourier transform (FT) is performed on the FID. • FT extracts the individual frequencies on the different nuclei; results in • a spectrum.

  14. Higher energy state: magnetic field opposes applied field How does NMR work? Nuclei are charged and if they have spin, they are magnetic Applied Magnetic Field = Bo Energy of transition = energy of radiowaves Lower energy state: magnetic field aligned with applied field

  15. An NMR Diagram: On the Inside RF transmitter RF Receiver N S Note modern NMRs use superconducting magnets to attain very strong magnetic fields + -

  16. Chemical Shifts Not all proton nuclei resonate at the same frequency. Proton nuclei are surrounded by electrons in slightly different chemical environments - nuclei are shielded by valance electrons that surround them. As a result, the nuclei are shielded from Bo to an extent that depends on the electron density around it. A shielded nucleus will feel a diminished Bo and will absorb radiofrequency radiation at a lower frequency - have a lower ppm value. A deshielded nucleus will feel a stronger Bo and will absorb radiofrequency radiation at a higher frequency - have a higher ppm value. Different nuclei will be shielded differently and, as a result, will have different resonance frequency - different ppm values - different chemical shifts.

  17. Chemical Shifts • Protons near an electronegative group will be deshielded - feel a stronger Bo - have a higher ppm value. • Electronegative groups: OH, OR, Cl, F, Br, N • Other deshielding groups: C=C, phenyl, C=O

  18. Shielding/Deshielding Effect

  19. 1H NMR Spectrum of Ethanol b c a a CH3CH2OH TMS Three signals - three different types of H’s b c downfield upfield ppm

  20. Chemical Shifts TMS - Tetramethylsilane (Me4Si) is the internal reference used. TMS’s chemical shift is set at zero since most peaks appear more downfield from it. • The Delta (d) Scale • An arbitrary scale • 1 d = 1 part per million (ppm) of the spectrometer operating frequency. • For example, if using an 80 MHz instrument to run a 1H NMR spectrum, • 1 d would be 1 ppm of 80,000,000 Hz, or 80 MHz. • Since the radiofrequency absorption of a nuclei depends on the magnetic • field strength, chemical shift in Hz would vary from instrument to • instrument. • Thus, report the nuclei absorption in relative terms (d) as opposed to • absolute terms (Hz). This way, the chemical shifts will be the same • for nuclei of a sample despite what instrument you use - leads to • correlation charts!

  21. Equivalent & Non-Equivalent Hydrogens As seen in the 1H NMR spectrum of ethanol, the number of signals equals the number of different types of protons in a compound. • General rules: • Protons attached to the same sp3 carbon are equivalent/homotopic (if there • are no chiral centers in the molecule; if there are, could be equivalent or • non-equivalent). • If there is symmetry in the molecule, protons that are symmetrical will • have the same signal, the same chemical shift and be equivalent. • Considerations: • Protons attached to the same sp2 carbon (in alkenes) need to be evaluated • for equivalency. • Methylene protons (on a CH2 group) are diastereotopic if a chiral center exists • the molecule and are therefore non-equivalent. •  Perform a substitution test to check for equivalency

  22. Equivalent & Non-Equivalent Hydrogens Consider the following molecules. Determine which protons are equivalent and non-equivalent. Predict the number of signals that would appear in the 1H NMR spectra of these compounds.

  23. Equivalent & Non-Equivalent Hydrogens • Considerations: • Protons attached to the same sp2 carbon (in alkenes) need to • be evaluated for equivalency. • Methylene protons (on a CH2 group) are diastereotopic if a • chiral center exists the molecule and are therefore non-equivalent. •  Perform a substitution test to check for equivalency

  24. Equivalent & Non-Equivalent Hydrogens Substitution Test: 1. Change questionable H’s to a different group like D. 2. Create two new molecules. 3. Compare these two new molecules.

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