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Riemann Sums & Definite Integrals. Section 5.3. Finding Area with Riemann Sums. Subintervals with equal width.
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Riemann Sums & Definite Integrals Section 5.3
Finding Area with Riemann Sums Subintervals with equal width • For convenience, the area of a partition is often divided into subintervals with equal width – in other words, the rectangles all have the same width. (see the diagram to the right and section 5-2)
Finding Area with Riemann Sums • It is possible to divide a region into different sized rectangles based on an algorithm or rule (see graph above and example #1 on page 307)
Finding Area with Riemann Sums • It is also possible to make rectangles of whatever width you want where the width and/or places where to take the height does not follow any particular pattern. Notice that the subintervals don’t seem to have a pattern. They don’t have to be any specific width or follow any particular pattern. Also notice that the height can be taken anywhere on each subinterval – not only at endpoints or midpoints!
What is a Riemann Sum Definition: Let f be defined on the closed interval [a,b], and let be a partition [a,b] given bya = x0 < x1 < x2 < … < xn-1 < xn = bwhere xi is the width of the ith subinterval [xi-1, xi]. If c is any point in the ith subinterval, then the sum is called a Riemann sum of f for the partition .
b - a n New Notation for x • When the partitions (boundaries that tell you where to find the area) are divided into subintervals with different widths, the width of the largest subinterval of a partition is the NORM of the partition and is denoted by |||| • If every subinterval is of equal width, the partition is REGULAR and the norm is denoted by||||= x = • The number of subintervals in a partition approaches infinity as the norm of the partition approaches 0. In other words, |||| 0 implies that n Is the converse of this statement true? Why or why not?
Definite Integrals If f is defined on the closed interval [a,b] and the limit exists, then f is integrable on [a,b] and the limit is denoted by The limit is called the definite integral of f from a to b. The number a is the lower limit of integration and the number b is the upper limit of integration.
Definite Integrals vs. Indefinite Integrals A definite integral is number. An indefinite integral is a family of functions. They may look a lot alike, however, • definite integrals have limits of integration while the • indefinite integrals have not limits of integration. Definite Integral Indefinite Integral
Theorem 5.4 Continuity Implies Integrability If a function f is continuous on the closed interval [a,b], then f is integrable on [a,b]. Is the converse of this statement true? Why or why not?
Evaluating a definite integral… To learn how to evaluate a definite integral as a limit, study Example #2 on p. 310.
Theorem 5.5The Definite Integral as the Area of a Region If f is continuous and nonnegative on the closed interval [a,b], then the area of the region bounded by the graph of f, the x-axis, and the vertical lines x = a and x = b is given by Area =
Let’s try this out… • Sketch the region • Find the area indicated by the integral. Area = (base)(height) = (2)(4) = 8 un2
Give this one a try… • Sketch the region • Find the area indicated by the integral. base2 =5 Area of a trapezoid = .5(width)(base1+ base2) = (.5)(3)(2+5) = 10.5 un 2 base1=2 Width =3
Try this one… • Sketch the region • Find the area indicated by the integral. Area of a semicircle = .5( r2) = (.5)()(22) = 2 un 2
Properties of Definite Integrals • If f is defined at x = a, then we define So, If f is integrable on [a,b], then we define So,
Theorem 5.6 Additive Interval Property If f is integrable on three closed intervals determined by a, b, and c, then
Theorem 5.7 Properties of Definite Integrals If f and g are integrable on [a,b] and k is a constant, then the functions of kf and f g are integrable on [a,b], and
HOMEWORK – yep…more practice Thursday, January 17 Read and take notes on section 5.3 and do p. 314 # 3, 6, 9, …, 45, 47, 49, 53, 65- 70 – Work on the AP Review Diagnostic Tests if you have time over the long weekend. Tuesday – January 22 – Get the Riemann sum program for your calculator and do p. 316 # 59-64, 71 and then READ and TAKE Notes on section 5-4 and maybe more to come!!