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Polar bonds and molecular polarity . Degrees between ionic and covalent. Sharing two electrons effectively doubles the count. In the molecule F 2 : Each atom wants 8 Alone each has seven Together they have eight Single covalent bond. H. H. O. O. H. H.
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Polar bonds and molecular polarity Degrees between ionic and covalent
Sharing two electrons effectively doubles the count • In the molecule F2: • Each atom wants 8 • Alone each has seven • Together they have eight • Single covalent bond
H H O O H H Covalent bonds between unlike elements • Oxygen requires octet – shares two electrons with H atoms (one with each) • Hydrogen requires two – each atom shares one electron with O
Lewis dot structures • In going from G4 – G7, a H atom is replaced by a lone pair of electrons • The total number of electrons is equal to the sum of all the valence electrons • The total number of electrons remains the same – 8 • Each atom has a complete octet
O O N N Multiple bonds are a feature • O2 and N2 do not achieve octets by sharing two electrons • Must share more electrons • O2 has double bond (four electrons shared) • N2 has triple bond (six electrons shared) – one of the strongest in chemistry • N2 is very stable and unreactive – also the major product from explosives
Properties of covalent compounds • Gases, liquids and solids at room temperature • May be hard or soft (diamond is a covalent solid) • May be soluble in polar or non-polar solvents • Solutions and melts do not conduct electricity • Most covalent compounds are molecular
Polar bonds • The ionic bond and the equally shared covalent bond are two extremes • Complete transfer of charge to equal sharing of charge • Many bonds fall in between: atoms of different elements have different attraction for electrons
Electronegativity • The degree to which an atom attracts electrons towards itself in a bond with another atom • highly electronegative atom attracts electrons • weakly electronegative atom does not
Table of electronegativity Least electronegative Most electronegative
Polar bonds and polar molecules • Any bond containing different elements will be polar to some degree • For a molecule to be polar will depend upon how the bonds are arranged • A molecule may contain polar bonds and be itself non-polar • We need to understand the molecular structure
Lewis dot structures: doing the dots • Molecular structure reduced to simplest terms showing only the arrangements of the valence electrons as dots in a 2-dimensional figure • Show only valence electrons • Electrons are either in: • bonds • lone pairs (stable molecules do not contain unpaired electrons – with very few exceptions) • Octet rule is guiding principle for distribution of electrons in the molecule
Lewis dot structures made easy • Start with the skeleton of the molecule • Least electronegative element is the central atom • S = N - A • N = number of electrons required to fill octet for each atom (8 for each element, except 2 for H and 6 for B) • A = number of valence electrons • S = number of electrons in bonds
Calculate N for the molecule Calculate A (all the dots), including charges where appropriate (add one for each –ve charge and subtract one for each +ve charge) Determine S from S = N – A Satisfy all octets and create number of bonds dictated by S (may be multiples) NF3 N = 8(N) + 3 x 8(F) = 32 A = 5(N) + 3 x 7(F) = 26 S = 32 – 26 = 6 F N F F N F F F Applying the rules
Two tests for dot structures • Are the number of dots in the molecule equal to the number of valence electrons? • Are all the octets satisfied? • If both yes structure is valid • If either no then back to the drawing board
S O O Example of sulphur dioxide • N = 24 (3 atoms @ 8) • A = 18 (S = 6, O = 2 x 6 = 12 valence electrons) • S = 6 (3 two-electron bonds) • 12 non-bonded electrons (6 pairs)
Expansion of the octet • Elements in second row invariably obey the octet rule • The heavy congeners regularly disobey it • Consider: • OF2 but SF6 • NCl3 but PCl5 • Octet expansion is a consequence of the availability of vacant 3d orbitals to the third row, where there are no 2d orbitals in the second row
Investigate with dot structures • Proceed with same S = N – A strategy • Octet expansion is indicated by the inability to obtain a reasonable solution
Consider SF4 • N = 40, A = 28 + 6 = 34 • S = 6 • 6 bonding electrons and 4 bonds! Means excess electrons • Make bonds and complete octets on peripheral atoms • Add the excess to the central atom
PCl5 • N = 48, A = 5 x 7 + 5 = 40 • S = 8 • 8 bonding electrons and 5 bonds • Proceed as before • In this case the octet expansion involves a bonded atom rather than a lone pair
Resonance: short-comings of the dot model • The dot structure of O3 (or SO2) can be drawn in two equivalent ways • Neither is correct in of itself • The “true” structure is an average of the two “resonance hybrids” • Lewis model considers bonds as being between two atoms • In many molecules, the bonding can involve 3 or more atoms • This phenomenon is called delocalization • In O3 the bonding electrons are delocalized over all three O atoms