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TRANSFORMING FORMULA

TRANSFORMING FORMULA. VARIABLES ON BOTH SIDES. LITERAL EQUATION. " solving literal equations " is another way of saying, "taking an equation with lots of letters , and solving for one letter in particular.". Examples of LITERAL EQUATIONS. d= rt d=distance r=rate t=time. A= ½(bh)

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TRANSFORMING FORMULA

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  1. TRANSFORMING FORMULA • VARIABLES ON BOTH SIDES

  2. LITERAL EQUATION "solving literal equations" is another way of saying, "taking an equation with lots of letters, and solving for one letter in particular."

  3. Examples of LITERAL EQUATIONS d= rt d=distance r=rate t=time A= ½(bh) A=area of a triangle b=base h=height P= 2w + 2l P=perimeter w=width l=length

  4. d= t r d= t r r t t t t =d r r =d t Solving Literal Equations Solve for r Solve for t d= rt d=distance r=rate t=time d= rt d= rt

  5. 2A = b b = 2A h h h h A= ½(bh) A=area of a triangle b=base h=height Solve for b A = ½ (bh) (2) A = ½ (bh) (2) 2A = (bh)

  6. h = 2A b YOUR TURN! Solve for h A= ½(bh) A=area of a triangle b=base h=height

  7. 2 2 P -2w = l 2 Solve for l P= 2w + 2l P=perimeter w=width l=length P = 2w + 2l -2w -2w P -2w = 2l

  8. 4 t= 3m-e d=(b-6k) Solve the following literal equations and write each step made b = 6k + 4d Solve for d m = ⅓ (t + e) Solve for t

  9. a= x - s 4 4 t= 3m-e s= x - 4a w=h - ⅓k k=3(h+w) d=(b-6k) Homework X = 4a + s Solve for a m = ⅓ (t + e) Solve for t X = 4a + s Solve for s b = 6k + 4d Solve for d h = ⅓k - w Solve for k h = ⅓k - w Solve for w

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