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THE SHELL GAME OR RIEMANN SUMS RE RE VISITED

THE SHELL GAME OR RIEMANN SUMS RE RE VISITED. Some solids of revolution are not amenable to the methods we have learned so far ( disks and washers ). For example, we may have to compute the volume of the solid of revolution generated by rotating the violet area around the y-axis .

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THE SHELL GAME OR RIEMANN SUMS RE RE VISITED

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  1. THE SHELL GAMEORRIEMANN SUMS REREVISITED Some solids of revolution are not amenable to the methods we have learned so far (disks and washers). For example, we may have to compute the volume of the solid of revolution generated by rotating the violet area around the y-axis. The volume of the solid of revolution generated by rotating about the x-axis is a piece of cake, we just did it in the last presentation! But the y-axis?

  2. What to do? Note that the solid you get is (roughly) half a bagel or half a doughnut. With the wisdom of Riemann sums (and of hind-sight!) we observe that the solid we get can be thought of as a sum of (more and more, thinner and thinner) “hollow cylinders”, called cylindrical shells obtained by rotating the Riemann “rectangles”

  3. shown in the figure Each small Riemann rectangle generates, by rotation about the y-axis, a cylindrical shell

  4. If one “unwraps” the cylindrical shell one gets (roughly) a parallelopiped with Height Base Width and Volume The volume of our solid of revolution (the half bagel!) is therefore the sum of these cylindrical shells. We get the formula Volume =

  5. Familiar? Recall our observation In our case, it computes the volume of our solid, and we can ease the computation via the FTC as Volume =

  6. Now life is fun! Let’s compute the volume of a full doughnut, obtained by rotating the circle shown about the y-axis. Of course, we will apply our formula to the figure shown in the next slide, with equation (then double the answer!)

  7. By the formula, volume of doughnut (formally torus) is Use substitution and two clever remarks to get the answer

  8. One more challenge: Find the volume of the “grooved” Bundt cake obtained by revolving the area shown in the figure about the y-axis. The equation of the red curve is

  9. Sometimes one is required to rotate the area bound by the graph of about the x-axis, but no convenient formula exists. (see figure) The red curve has equation

  10. The analysis we just made applies (mutatis mutandis, i.e. exchanging with ) and we get the volume as For the example shown we get: Computation of the integral requires integration by parts, to be learned next semester.

  11. The tables below may be helpful:

  12. and

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