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Two step Mole Problems

Two step Mole Problems. Why do we need moles???. You can NOT directly convert from grams to particles!!! You must go through MOLES!!!!. 2 Step Problems. Avogadro’s Number. Grams Moles Particles. MM. 1 gram 1 mole. 6.022x10 23 particles 1 mole.

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Two step Mole Problems

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  1. Two step Mole Problems

  2. Why do we need moles??? • You can NOT directly convert from grams to particles!!! • You must go through MOLES!!!!

  3. 2 Step Problems Avogadro’s Number Grams Moles Particles MM 1 gram 1 mole 6.022x1023 particles 1 mole

  4. Ex: How many atoms of Cu are present in 35.4 grams of Cu? 6.022x1023 atoms 1 mole 35.4 g x x = 3.35 x1023 atoms Cu 1 mole 63.55 g Cu MM AN

  5. What is the mass of 1.20x1024 molecules of glucose (C6H12O6)? • You are going to need the molar mass of glucose!!!! • MM = 180.18 g glucose/mole 1.20x1024 molecules x 1 mole x 180.18 g 1 mole 6.02x1023 molecules AN MM = 359 g C6H12O6

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