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Chemical Reactions – Part 1 Balancing Chemical Equations

Chemical Reactions – Part 1 Balancing Chemical Equations. Lesson Essential Question…. How do I balance a chemical equation?. Parts of a Chemical Reaction. 2 NaCl (aq ) + Ag 2 SO 4(aq) Na 2 SO 4(aq) + 2 AgCl ( s ). States of Matter ( aq ) – aqueous

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Chemical Reactions – Part 1 Balancing Chemical Equations

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  1. Chemical Reactions – Part 1Balancing Chemical Equations

  2. Lesson Essential Question… How do I balance a chemical equation?

  3. Parts of a Chemical Reaction 2 NaCl(aq) + Ag2SO4(aq) Na2SO4(aq) + 2AgCl(s) States of Matter (aq) – aqueous (s) – solid (ppt or solid) - liquid (ex. H20, Br2) (g) – gas (ex. H2, O2) COEFFICIENTS These numbers are from balancing the equation. They are the number of “moles” of each compound indicating the ratio of each reactant to product formed. ??? State of matter after the reaction. Use solubility rules to determine state. ??? ??? States of matter at room temperature before reaction started. ??? Reactants Yields ??? Products ???

  4. Think back to the Law of Conservation of Matter What did it say? “No matter can be created nor destroyed in an ordinary chemical reaction.”

  5. With that in mind… The equation is now balanced according to the Law of Conservation of Matter so how do we show that with the chemical equation? Lets look at it on the molecular level. COEFFICIENTS Evaluate the chemical reaction below. Does it support the Law of Conservation of Matter? On the product side there is one oxygen atom so another water molecule needs to be added to the product side. Add another hydrogen molecule to the reactant side giving a total of four hydrogen atoms on the reactant side. On the product side there are two hydrogen atoms. So far hydrogen is balanced. Lets look at hydrogen first. On the reactant side there are two hydrogen atoms. Now there are four hydrogen atoms on the product side. For oxygen: there are two oxygen atoms on the reactant side. O H H O O O H H H H H H 2 2 H2 O2 H2O +

  6. Try Balancing this combustion reaction… The equation is now balanced according to the Law of Conservation of Matter so how do we show that with the chemical equation? Lets look at it on the molecular level. COEFFICIENTS On the product side there are two hydrogen atoms. So you need to add another water molecule. Now there are four oxygen atoms on the product side. Add another oxygen molecule to the reactant side giving a total of four oxygen atoms on the reactant side. Lets look at hydrogen first. On the reactant side there are four hydrogen atoms. There is one carbon on the product side There is one carbon on the reactant side This symbol on top of the “yields” arrow indicates that heat or burning was involved. O O H H H O H O O C H O O C H H O H 2 2 CH4 + O2 CO2 + H2O

  7. Try Balancing These Equations… 2 3 2 1. Al + Fe3N2 AlN + Fe 3 2 2 2. NaClO3 NaCl + O2 3 2 6 3. BF3 + Li2SO3 B2(SO3)3 + LIF 3 3 4. Sn(NO2)4 + Pt3N4 Sn3N4 + Pt(NO2)4 6 2 6 5. B2Br6 + HNO3 B(NO3)3 + HBr

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