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Students are provided with scaled graph papers with problems written on them as the handouts.

Solve and Graph: 3x+6y=12. Students are provided with scaled graph papers with problems written on them as the handouts. শিক্ষার্থীরা বিলিপত্র হিসাবে তাদের লিখিত সমস্যার সঙ্গে আঁশযুক্ত গ্রাফ কাগজপত্র সঙ্গে উপলব্ধ করা হয়. Solve and Graph: 3x+6y < 12.

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Students are provided with scaled graph papers with problems written on them as the handouts.

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  1. Solve and Graph: 3x+6y=12 Students are provided with scaled graph papers with problems written on them as the handouts. শিক্ষার্থীরা বিলিপত্র হিসাবে তাদের লিখিত সমস্যার সঙ্গে আঁশযুক্ত গ্রাফ কাগজপত্র সঙ্গে উপলব্ধ করা হয়.

  2. Solve and Graph: 3x+6y < 12 Students are provided with scaled graph papers with problems written on them as the handouts.

  3. Solve and Graph: 2x - 3y < 6 Students are provided with scaled graph papers with problems written on them as the handouts.

  4. Solve and Graph: X + 5y <= -10 Students are provided with scaled graph papers with problems written on them as the handouts.

  5. Students are provided with scaled graph papers with problems written on them as the handouts. Solve and Graph: X > 5

  6. Students are provided with scaled graph papers with problems written on them as the handouts. Solve and Graph: -3y < 21

  7. 5 min + 5 min discussion • এক বিলিপত্র নিন • লাল এবং নীল কলম আছে. • আপনার বেল কাজ লাল কলম ব্যবহার করুন. • বেল কাজ শুরু করুন. Do Now Bell Work Take one handout Have red and blue pen. Use red pen to do your Bell work. Start Bell work. Solve and graph. Shamdhan & Grapha 3x + 6y = 12 After 5 minutes students will be asked to stop wherever they are and change the pen. Class will review the bellwork together.

  8. 5 min + 5 min discussion Bell Work Technique 2: 3x + 6y = 12 ---------- 1 Find y intercept = b (when x=0) Plug value of x =0 in eq. 1 3(0)+6y=12 6y=12 divide by 6 on both sides 6 y = 2, point is (0,2) Find X intercept (when y=0) 3x+6(0)=12 3x = 12 3 x = 4, point is (4,0) Bell Work Solve and graph. Shamdhan & Graph 3x + 6y = 12 Discussion: Technique 1: 3x + 6y = 12 -3x = -3x subtract 3x from both sides 6y = -3x + 12divide by 6 to get y by itself 6 6 6 y = -1/2 x + 2 y = mx +b m= rise/ run= -1/2 and b= 2 ;(0,2)

  9. Students: Locate point (4,0) ছাত্ররা: বিন্দু নির্ণয় করুন (4.0) (0,2) Students: Locate point (0,2) ছাত্ররা: বিন্দু নির্ণয় করুন (4.0) (4,0)

  10. Linear Inequalities in Two Variables Solve and graph: সমাধান এবং গ্রাফ 3x + 6y < 12 Again, I just did that! Yes but now you have an inequality rather than equality. হ্যাঁ কিন্তু এখন আপনি বরং সমতা আর একটা বৈষম্য আছে.

  11. 15 min explanation Remember that the first step is to just graph it like it’s an equation. Graph: 3x + 6y < 12 From bell work; two points are (4,0) and (0,2) TEACHERS NOTES Now before we just draw a line, what else should we think about? (whether it should be solid or dashed) – so which one is it? how do you know? ------------ if < or > ; ____________ if <= or >= And what’s the last thing we need to do is shade. How do we know what area to shade? Test a point. If it’s a solution set. 3x+6y < 12 Choose a point on coordinate plane e.g. (-7,3) Let students try the second one on their own, then poll for answers… (what does the line look like? why? is it solid or dashed? why? shade below or above? where is “below” on this graph?) Now Graph. Linear Inequalities in Two Variables

  12. Solution Set: সমাধান সেটের Choose a point on the coordinate plane. Check if the point is a solution set? তএকটি বিন্দু বেছে নিন If the inequality is true then the point is a solution; if false NOT a solution বিন্দু একটি সমাধান সেট করা হলে পরীক্ষা করে দেখুন! বৈষম্য সত্য, তাহলে বিন্দু একটি সমাধান; যদি মিথ্যা না একটি সমাধান(-7,3) 3x +6y < 12 2(-7)+6(3) < 12 -14 + 18 < 12 True (0,2) (4,0)

  13. 5 min খুঁজুন Y পথিমধ্যে = খ (যখন x = 0) EQ মধ্যে এক্স = 0 মান বসান. 1 2 (0)-3 বর্ষ <6 উভয় পক্ষের-3 বর্ষ <(-3) দ্বারা 6 ডিভাইড ফ্লিপ "<" যাও ">"   Y> -2 বিন্দু (0, -2) এক্স পথিমধ্যে খুঁজুন (y = যখন 0) Y = 0 এর valus রাখুন. 1 2x-3 (0) <6 উভয় পক্ষের 2 দ্বারা 2x <6 ডিভাইড   এক্স <3 পয়েন্ট (3, 0) Linear Inequalities in Two Variables Solve/ Shamdhan: 2x-3y < 6 _____1 Find y intercept = b (when x=0) Put value of x =0 in eq. 1 2(0)-3y<6 -3y<6 divide by (-3) on both sides *Flip “<“ to “>” y > -2 point is (0,-2) Find X intercept (when y=0) Put the valus of y=0 in eq. 1 2x-3(0) < 6 2x < 6 divide by 2 on both sides x < 3point is (3 ,0)

  14. Solution Set: Choose a point on the coordinate plane. Check if the point is a solution set? If the inequality is true then the point is a solution; if false NOT a solution (10,3) 2x -3y < 6 2(10)+3(3) < 6 20 + 9 < 6False (0,-2) (3,0)

  15. 5 min Linear Inequalities in Two Variables Solve/Shamdhan: x + 5y <= -10 _____ eq.1 Find y intercept = b (when x=0) Plug value of x =0 in eq. 1 (0)+5y<= -10 5y<= - 10 divide by (5) on both sides. y <= -2 point is (0,-2) Find X intercept (when y=0) Put the valus of y=0 in eq. 1 x+5(0) <= -10 x < -10 point is (-10 ,0)

  16. Solution Set: Choose a point on the coordinate plane. Check if the point is a solution set? If the inequality is true then the point is a solution; if false NOT a solution (-6,-6) x +5y <= -10 -6 + 5(-6) <=-10 -36 <= -10 True (0,-2) (-10,0)

  17. 3 min Linear Inequalities in Two Variables Solve: x > 5 (111;5) TEACHERS NOTES Remember: Graph it like it’s an equation – this equation is a little weird because we only have one variable. How do we graph x > 5? (a vertical line) How do remember this? Now before we just draw a line, what else should we think about? (whether it should be solid or dashed) – so which one it it? how do you know? And what’s the last thing we need to do? (shade right hand side area because we want to shade all the x’s that are GREATER THAN 5)

  18. Which area to shade? Students will be asked to choose point of their choice, to find solution set Linear Inequalities in two variables

  19. 3 min Linear Inequalities in Two Variables Solve/ Shamdhan: (111,21) -3y < 21 *y is –ve; -3y < 21 divide by (-3) on both sides *Flip “<“ to “>” y >-7 TEACHERS NOTES: How do we graph x > -7? (a horizontal line) whether it should be solid or dashed) – so which one it it? Where to shade ? ABOVE because we want to shade all the y’s that are GREATER THAN -7)

  20. Which area to shade? Students will be asked to choose point of their choice, to find solution set Linear Inequalities in two variables

  21. 10 min Linear Inequalities in Two Variables On Your Own: Please Use red pen to do these problems. Do: Page 111; 19,22,28,29 Hint: How to Graph: Find: x-intercept (value of x when y=0) ;(x,0) y-intercept (value of y when x=0) OR“b” ; (0,y) Use ---- if < or > , _______ if <= or >= Choose another point to test the solution set. Shade the half plane of the solution set.

  22. Linear Inequalities in Two Variables Observation: What is the difference between the graph of 3x + 6y = 12 And 3x + 6y < 12

  23. Linear Inequalities in Two Variables Observation / Porgobeckhen: What is the difference between the graph of 3x + 6y = 12 The graph of a linear equation in two variable is a Line. দুটি ভেরিয়েবল একটি রৈখিক সমীকরণের গ্রাফ হল একটি লাইন. And 3x + 6y < 12 The graph of a linear inequality in two variables divides the coordinate plane into two half-planes. দুটি ভেরিয়েবল একটি রৈখিক বৈষম্য গ্রাফ দুটি অর্ধ প্লেন মধ্যে সমন্বয় সাধন সমতল ভাগ করা হয়.

  24. Linear Inequalities in Two Variables Mathematically: A linear inequality in two variables is an equality that can be written in one of the following forms: দুটি ভেরিয়েবল একটি রৈখিক বৈষম্য নিম্নলিখিত ধরনের এক লেখা যাবে যে সমতা হয়: Ax+By < C or Ax+By <= C Ax+BY > C or Ax+By >= C

  25. Linear Inequalities in Two Variables Application: Critical Thinking You and your friend can spend no more than $30 at a health club. It costs $10 an hour to use the racquet ball and $5 an hour to use the tennis court. Find can you and your friend do with this money at health club. আপনি এবং আপনার বন্ধু একটি হেলথ ক্লাবে এ কোন অধিক $ 30 ব্যয় করতে পারেন. এটা টেনিস কোর্ট ব্যবহার করতে টেনিস্ খেলের ব্যাট বল ব্যবহার এবং $ 5 এক ঘন্টা থেকে $ 10 একটি ঘন্টা খরচ. আপনি এবং আপনার বন্ধু স্বাস্থ্য ক্লাব এই টাকা দিয়ে কি করতে পারেন খুঁজুন. TEACHERS NOTES: Discussion : Student were asked to think about and come up with the several answers. Teacher will correlate that answers as being member of solution set and how to graph linear inequality. More detailed discussion on how to solve it algebraically and numerically and compare and contrast the both technique is the focus of next class.

  26. Linear Inequalities in Two Variables Home work : Page 111 ; problem 28-32 even Exit Ticket: Please drop “Bell Work” and “On you Own” Work before you leave. Teacher can evaluate the progress they made from bell work to class work with the use of red colored pen. Red pen is the work they did on their own while blue is we did together as a class.

  27. Linear Inequalities in Two Variables Reflection: This group of students is diversified in terms of cognitive abilities as well as ethnicity. To meet the needs of all diverse learners, I tried to implement two things: Broke down the lesson in extremely simple easy to understand step, translate the key words in bangla (as 7 out of 19 girls are ELL and barely can speak and understand English). In my opinion the lesson is very engaging and prompt questions during all the activities will keep the busy and not distracted. Overall, In my opinion, the lesson will really well. We as a class will solve 5 problems before them attempting one on their own. I will called on students by random lottery so there is a chance for everyone and eliminate volunteering as I have noticed that only smart students come to board or answer the question. In this way more timid students will get a chance to practice speaking. I wish I had included more communicative activities involving the students. That way they would get more of the practice they need. I am really excited about teaching this topic in the class this Thursday. I am pretty much confident that I will be able to achieve what my goals and objectives are for this lesson plan. For this lesson, I could start from the critical thinking question, which I posed at the end of the class and derive from them back to “ how to graph “ and the “solution set” butright now I am interested in behaviorism as students are struggling with the basic facts but lesson was garnished with some critical thinking and constructivism.

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